以下代码的输出结果为() let a:Set<Int> = [2,3,4,5,6] let b:Set<Int> = [5,6,7,8,9] print(a.intersect(b).sort0)
时间: 2024-05-18 11:12:40 浏览: 14
该代码会抛出编译错误。原因是:
1. 在Swift中,初始化Set需要使用花括号{},而不是中括号[]。因此,正确的初始化方式应该是:
```
let a: Set<Int> = [2, 3, 4, 5, 6]
let b: Set<Int> = [5, 6, 7, 8, 9]
```
2. 在Swift中,Set的intersect方法返回一个新的Set,其中包含两个Set的交集。然而,由于Set是一个无序的集合,因此我们无法保证输出结果的顺序。因此,我们需要在调用intersect方法后使用sorted方法对结果进行排序。
因此,正确的代码应该是:
```
let a: Set<Int> = [2, 3, 4, 5, 6]
let b: Set<Int> = [5, 6, 7, 8, 9]
print(a.intersection(b).sorted())
```
输出结果应该为:[5, 6]。
相关问题
error: value of type 'Set<Int>' has no member 'sorted' let sortedIntSet = intSet.sorted() ^~~~~~ ~~~~~~
这个错误是因为 Set 类型没有 sorted() 方法,你可以将 Set 转换成 Array 类型,然后再使用 sorted() 方法来排序。以下是示例代码:
let sortedIntSet = Array(intSet).sorted()
#43: FILE: test/test_timer.c:143: + static int init = 0;$ ERROR: do not initialise statics to 0
The error message is telling you not to initialize static variables to 0 explicitly. In C, static variables are implicitly initialized to 0, so there is no need to explicitly set them to 0.
To fix the error, you can simply remove the initialization of the static variable `init` to 0, and let the variable be implicitly initialized to 0. For example:
```
static int init;
```
This will ensure that the static variable is correctly initialized to 0, and avoid the error message.
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