你能写一个coons曲面的实现代码吗
时间: 2023-07-16 20:13:00 浏览: 60
当然可以,以下是一个基于Python的Coons曲面实现代码:
```python
import numpy as np
import matplotlib.pyplot as plt
from mpl_toolkits.mplot3d import Axes3D
def coons_patch(p1, p2, q1, q2, f1, f2, g1, g2):
"""
Implementation of Coons patch.
Parameters:
p1, p2: 1D arrays of n points representing the boundary curve for the first variable.
q1, q2: 1D arrays of m points representing the boundary curve for the second variable.
f1, f2: 1D arrays of n points representing the boundary curve for the first function.
g1, g2: 1D arrays of m points representing the boundary curve for the second function.
Returns:
X, Y, Z: 2D arrays representing the Coons patch.
"""
n = len(p1)
m = len(q1)
# Construct the two blending functions.
B1 = [(1 - t) * f1[i] + t * f2[i] for i in range(n)]
B2 = [(1 - t) * g1[i] + t * g2[i] for i in range(m)]
# Construct the Coons patch.
X = np.zeros((n, m))
Y = np.zeros((n, m))
Z = np.zeros((n, m))
for i in range(n):
for j in range(m):
X[i, j] = (1 - t) * p1[i] * B2[j] + t * p2[i] * B2[j] + \
(1 - s) * q1[j] * B1[i] + s * q2[j] * B1[i] - \
(1 - s) * (1 - t) * p1[0] * q1[0] - s * (1 - t) * p1[0] * q2[-1] - \
(1 - s) * t * p2[-1] * q1[0] - s * t * p2[-1] * q2[-1]
Y[i, j] = (1 - t) * p1[i] * q2[j] + t * p2[i] * q2[j] + \
(1 - s) * q1[j] * B1[i] + s * q2[j] * B1[i] - \
(1 - s) * (1 - t) * p1[0] * q1[0] - s * (1 - t) * p1[0] * q2[-1] - \
(1 - s) * t * p2[-1] * q1[0] - s * t * p2[-1] * q2[-1]
Z[i, j] = (1 - t) * f1[i] * g2[j] + t * f2[i] * g2[j] + \
(1 - s) * f1[i] * B2[j] + s * f2[i] * B2[j]
return X, Y, Z
# Define the boundary curves and functions.
p1 = np.array([0, 1, 2, 3])
p2 = np.array([-1, 0, 1, 2])
q1 = np.array([0, 1, 2, 3])
q2 = np.array([1, 2, 3, 4])
f1 = np.array([0, 1, 2, 3])
f2 = np.array([1, 2, 3, 4])
g1 = np.array([0, 1, 2, 3])
g2 = np.array([2, 3, 4, 5])
# Construct the Coons patch.
s = np.linspace(0, 1, 100)
t = np.linspace(0, 1, 100)
S, T = np.meshgrid(s, t)
X, Y, Z = coons_patch(p1, p2, q1, q2, f1, f2, g1, g2)
# Plot the Coons patch.
fig = plt.figure()
ax = fig.add_subplot(111, projection='3d')
ax.plot_surface(X, Y, Z, cmap='viridis')
ax.set_xlabel('X')
ax.set_ylabel('Y')
ax.set_zlabel('Z')
plt.show()
```
这个实现代码只是一个简单的例子,您可以根据需要对其进行修改和扩展。