select *,rank()over(order by price desc) from sql7报错 FROM keyword not found where expecte
时间: 2024-05-04 10:21:17 浏览: 13
这个 SQL 语句有一些语法错误。正常的写法应该是:
```
SELECT *, RANK() OVER (ORDER BY price DESC)
FROM sql7
WHERE keyword = 'not found' AND expected IS NULL;
```
这个查询语句的功能是从表 `sql7` 中选择所有行和列,并按照价格从高到低进行排名。同时,过滤掉 `keyword` 列不等于 `'not found'` 或者 `expected` 列不为 `NULL` 的行。
相关问题
select *,rank()over(order by price desc) from sql7 为什么会报错FROM keyword not found where expecte
这个 SQL 语句缺少 WHERE 子句,应该使用类似于以下的语法:
```sql
SELECT *, RANK() OVER (ORDER BY price DESC)
FROM sql7
WHERE ...
```
其中的 `WHERE` 子句用于指定要筛选的行。如果不需要筛选,可以使用 `WHERE 1=1` 或者直接省略 `WHERE` 子句。
TypeError: one character bytes, bytearray or integer expecte
d, got 'str'
This error occurs when you try to perform an operation on a string instead of a byte, bytearray, or integer object.
For example, let's say you have a string 'hello' and you try to use the ord() function on it to get the ASCII value of the first character:
```
s = 'hello'
print(ord(s[0]))
```
This will result in the error message above because the ord() function expects a byte, bytearray, or integer object as input, not a string.
To fix this error, you need to convert the string to an appropriate object. In this case, you can convert the string to a bytearray:
```
s = 'hello'
b = bytearray(s, 'utf-8')
print(ord(b[0]))
```
This will correctly output the ASCII value of the first character in the string.