python实现三人对决

以下是一个简单的Python程序，模拟三人对决的过程：

import random

# 定义三个角色的属性
player1 = {'name': 'Alice', 'hp': 100, 'atk': 20}
player2 = {'name': 'Bob', 'hp': 100, 'atk': 20}
player3 = {'name': 'Charlie', 'hp': 100, 'atk': 20}

# 定义游戏结束的条件
def game_over():
    return player1['hp'] <= 0 or player2['hp'] <= 0 or player3['hp'] <= 0

# 定义角色攻击的函数
def attack(attacker, target):
    damage = random.randint(1, attacker['atk'])
    target['hp'] -= damage
    print(f"{attacker['name']} attacked {target['name']} and caused {damage} damage.")
    if target['hp'] <= 0:
        print(f"{target['name']} is defeated!")

# 开始游戏
while not game_over():
    # 随机选择一个攻击者和一个目标
    attacker = random.choice([player1, player2, player3])
    target = random.choice([player1, player2, player3])
    # 如果攻击者和目标相同，则重新选择目标
    while target == attacker:
        target = random.choice([player1, player2, player3])
    # 攻击
    attack(attacker, target)

# 游戏结束，输出最终结果
if player1['hp'] > 0:
    print(f"{player1['name']} wins!")
elif player2['hp'] > 0:
    print(f"{player2['name']} wins!")
else:
    print(f"{player3['name']} wins!")

运行上述程序，可以看到三个角色交替攻击，直到只有一个角色存活为止。程序会输出最终胜者的名字。