C语言实现模拟扑克牌发牌，只考虑四种花色的共52张牌，不考虑大鬼和小鬼，每人发十三张牌

好的，以下是实现模拟扑克牌发牌的C语言代码：

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

#define CARD_NUM 52
#define PLAYER_NUM 4
#define CARD_TYPE_NUM 4
#define CARD_NUM_PER_TYPE 13

// 牌的结构体
typedef struct {
    int type; // 花色，0-3表示黑桃、红心、梅花、方块
    int num; // 点数，1-13表示A到K
} Card;

// 初始化牌组
void init_cards(Card *cards) {
    for (int i = 0; i < CARD_TYPE_NUM; i++) {
        for (int j = 0; j < CARD_NUM_PER_TYPE; j++) {
            cards[i * CARD_NUM_PER_TYPE + j].type = i;
            cards[i * CARD_NUM_PER_TYPE + j].num = j + 1;
        }
    }
}

// 洗牌
void shuffle_cards(Card *cards) {
    srand(time(NULL)); // 设置随机种子
    for (int i = CARD_NUM - 1; i >= 1; i--) {
        int j = rand() % (i + 1); // 生成0到i之间的随机数
        Card temp = cards[i];
        cards[i] = cards[j];
        cards[j] = temp;
    }
}

// 输出牌的信息
void print_card(Card card) {
    const char *type_strs[] = {"黑桃", "红心", "梅花", "方块"};
    const char *num_strs[] = {"A", "2", "3", "4", "5", "6", "7", "8", "9", "10", "J", "Q", "K"};
    printf("%s%s ", type_strs[card.type], num_strs[card.num - 1]);
}

// 输出玩家的牌
void print_player_cards(int player_id, Card *cards) {
    printf("玩家%d的牌：", player_id);
    for (int i = 0; i < CARD_NUM_PER_TYPE; i++) {
        print_card(cards[player_id * CARD_NUM_PER_TYPE + i]);
    }
    printf("\n");
}

int main() {
    Card cards[CARD_NUM];
    init_cards(cards); // 初始化牌组
    shuffle_cards(cards); // 洗牌

    // 发牌
    Card player_cards[PLAYER_NUM][CARD_NUM_PER_TYPE];
    for (int i = 0; i < CARD_NUM_PER_TYPE; i++) {
        for (int j = 0; j < PLAYER_NUM; j++) {
            player_cards[j][i] = cards[i * PLAYER_NUM + j];
        }
    }

    // 输出每个玩家的牌
    for (int i = 0; i < PLAYER_NUM; i++) {
        print_player_cards(i, player_cards[i]);
    }

    return 0;
}

你可以直接将上述代码复制粘贴到C语言的开发环境中进行编译运行。希望能够帮到你。