java获取多层相同JSON数据的所有数据,以集合进行输出，详细代码

假设我们有以下的 JSON 数据：

{
  "data": [
    {
      "id": 1,
      "name": "Alice",
      "children": [
        {
          "id": 2,
          "name": "Bob",
          "children": [
            {
              "id": 3,
              "name": "Charlie",
              "children": [
                {
                  "id": 4,
                  "name": "David",
                  "children": []
                },
                {
                  "id": 5,
                  "name": "Emily",
                  "children": []
                }
              ]
            }
          ]
        }
      ]
    }
  ]
}

我们要获取所有的 `id` 和 `name`，以集合方式输出。可以用递归的方式来解决这个问题。下面是 Java 代码的实现：

import com.alibaba.fastjson.JSONArray;
import com.alibaba.fastjson.JSONObject;

import java.util.ArrayList;
import java.util.List;

public class Main {
    public static void main(String[] args) {
        String jsonStr = "{\n" +
                "  \"data\": [\n" +
                "    {\n" +
                "      \"id\": 1,\n" +
                "      \"name\": \"Alice\",\n" +
                "      \"children\": [\n" +
                "        {\n" +
                "          \"id\": 2,\n" +
                "          \"name\": \"Bob\",\n" +
                "          \"children\": [\n" +
                "            {\n" +
                "              \"id\": 3,\n" +
                "              \"name\": \"Charlie\",\n" +
                "              \"children\": [\n" +
                "                {\n" +
                "                  \"id\": 4,\n" +
                "                  \"name\": \"David\",\n" +
                "                  \"children\": []\n" +
                "                },\n" +
                "                {\n" +
                "                  \"id\": 5,\n" +
                "                  \"name\": \"Emily\",\n" +
                "                  \"children\": []\n" +
                "                }\n" +
                "              ]\n" +
                "            }\n" +
                "          ]\n" +
                "        }\n" +
                "      ]\n" +
                "    }\n" +
                "  ]\n" +
                "}";
        JSONObject jsonObj = JSONObject.parseObject(jsonStr);
        List<JSONObject> result = new ArrayList<>();
        getAllIdsAndNames(jsonObj.getJSONArray("data"), result);
        System.out.println(result);
    }

    private static void getAllIdsAndNames(JSONArray jsonArray, List<JSONObject> result) {
        for (int i = 0; i < jsonArray.size(); i++) {
            JSONObject obj = jsonArray.getJSONObject(i);
            JSONObject newObj = new JSONObject();
            newObj.put("id", obj.getInteger("id"));
            newObj.put("name", obj.getString("name"));
            result.add(newObj);
            JSONArray children = obj.getJSONArray("children");
            if (children != null && children.size() > 0) {
                getAllIdsAndNames(children, result);
            }
        }
    }
}

输出结果为：

[{"id":1,"name":"Alice"},{"id":2,"name":"Bob"},{"id":3,"name":"Charlie"},{"id":4,"name":"David"},{"id":5,"name":"Emily"}]