五子棋小游戏C语言VSCode

好的，我可以为您提供一份基于C语言和VSCode的五子棋小游戏代码。请注意，由于字符界面限制，该游戏不支持鼠标操作。以下是代码：

#include <stdio.h>
#include <stdlib.h>

#define ROWS 15
#define COLS 15

char board[ROWS][COLS]; // 保存棋盘状态
char player = 'X'; // 当前玩家棋子

// 初始化棋盘
void init_board()
{
    for (int i = 0; i < ROWS; i++) {
        for (int j = 0; j < COLS; j++) {
            board[i][j] = '-';
        }
    }
}

// 打印棋盘
void print_board()
{
    printf("   ");
    for (int i = 0; i < COLS; i++) {
        printf("%d ", i + 1);
    }
    printf("\n");
    for (int i = 0; i < ROWS; i++) {
        printf("%2d ", i + 1);
        for (int j = 0; j < COLS; j++) {
            printf("%c ", board[i][j]);
        }
        printf("\n");
    }
}

// 判断是否胜利
int is_win(int row, int col)
{
    // 判断横向是否有5个棋子相连
    int count = 1;
    for (int i = col - 1; i >= 0; i--) {
        if (board[row][i] == player) {
            count++;
        } else {
            break;
        }
    }
    for (int i = col + 1; i < COLS; i++) {
        if (board[row][i] == player) {
            count++;
        } else {
            break;
        }
    }
    if (count >= 5) {
        return 1;
    }

    // 判断纵向是否有5个棋子相连
    count = 1;
    for (int i = row - 1; i >= 0; i--) {
        if (board[i][col] == player) {
            count++;
        } else {
            break;
        }
    }
    for (int i = row + 1; i < ROWS; i++) {
        if (board[i][col] == player) {
            count++;
        } else {
            break;
        }
    }
    if (count >= 5) {
        return 1;
    }

    // 判断左上-右下是否有5个棋子相连
    count = 1;
    for (int i = row - 1, j = col - 1; i >= 0 && j >= 0; i--, j--) {
        if (board[i][j] == player) {
            count++;
        } else {
            break;
        }
    }
    for (int i = row + 1, j = col + 1; i < ROWS && j < COLS; i++, j++) {
        if (board[i][j] == player) {
            count++;
        } else {
            break;
        }
    }
    if (count >= 5) {
        return 1;
    }

    // 判断左下-右上是否有5个棋子相连
    count = 1;
    for (int i = row + 1, j = col - 1; i < ROWS && j >= 0; i++, j--) {
        if (board[i][j] == player) {
            count++;
        } else {
            break;
        }
    }
    for (int i = row - 1, j = col + 1; i >= 0 && j < COLS; i--, j++) {
        if (board[i][j] == player) {
            count++;
        } else {
            break;
        }
    }
    if (count >= 5) {
        return 1;
    }

    return 0;
}

// 玩家下棋
void player_move()
{
    int row, col;
    do {
        printf("请输入下棋位置(row col): ");
        scanf("%d %d", &row, &col);
        row--;
        col--;
    } while (row < 0 || row >= ROWS || col < 0 || col >= COLS || board[row][col] != '-');
    board[row][col] = player;
}

// 电脑下棋
void computer_move()
{
    // TODO: 实现电脑下棋功能
}

int main()
{
    init_board();

    while (1) {
        print_board();

        if (player == 'X') {
            player_move();
        } else {
            computer_move();
        }

        if (is_win()) {
            printf("游戏结束，%c方胜利！\n", player);
            break;
        }

        player = player == 'X' ? 'O' : 'X';
    }

    return 0;
}

该五子棋小游戏以字符界面形式展示，玩家通过输入行列坐标下棋，电脑暂未实现下棋功能。您可以根据需要自行修改代码。