补全代码 int size = 5; // 三角形的大小 for (int i = 1; i <= size; i++) { for (int j = 1; j <= size - i; j++) { System.out.print(" "); // 打印空格 } for (int k = 1; k <= i; k++) { System.out.print("*"); // 打印星号 } System.out.println(); // 换行 }
时间: 2024-01-03 11:03:49 浏览: 27
完整代码如下:
```java
int size = 5; // 三角形的大小
for (int i = 1; i <= size; i++) {
for (int j = 1; j <= size - i; j++) {
System.out.print(" "); // 打印空格
}
for (int k = 1; k <= i; k++) {
System.out.print("*"); // 打印星号
}
System.out.println(); // 换行
}
```
这段代码可以输出一个大小为5的三角形,效果如下:
```
*
**
***
****
*****
```
相关问题
将代码补充完整 using System; using System.Collections.Generic; using System.Text; namespace one { /// <summary> /// 班级 /// </summary> class Classes { private int _count;//学生人数 private int _size;//允许存储学生人数的最大值 Student[] Data;//学生信息集 public Classes() { //编写代码 } public int Count { get {return _count;} //编写代码 } /// <summary> /// 增加学生 /// </summary> /// <param name="s">学生</param> public void Add(Student s) { if (_count < _size) { //编写代码 } } /// <summary> /// 删除学生信息 /// </summary> /// <param name="Code">学号</param> public void Delete(string Code) { int i, p; for (i = 0; i < _count && Data[i].code != Code; i++) ; if (i < Count) { for (p = i; p < _count; p++) //编写代码 _count--; } } public Student this[int index] { get { if (index <= Count) return Data[index - 1]; else return null; } } } }
using System;
using System.Collections.Generic;
using System.Text;
namespace one
{
/// <summary>
/// 班级
/// </summary>
class Classes
{
private int _count;//学生人数
private int _size;//允许存储学生人数的最大值
Student[] Data;//学生信息集
public Classes(int size)
{
_count = 0;
_size = size;
Data = new Student[size];
}
public int Count
{
get { return _count; }
}
/// <summary>
/// 增加学生
/// </summary>
/// <param name="s">学生</param>
public void Add(Student s)
{
if (_count < _size)
{
Data[_count++] = s;
}
}
/// <summary>
/// 删除学生信息
/// </summary>
/// <param name="Code">学号</param>
public void Delete(string Code)
{
int i, p;
for (i = 0; i < _count && Data[i].code != Code; i++) ;
if (i < Count)
{
for (p = i; p < _count - 1; p++)
Data[p] = Data[p + 1];
_count--;
}
}
public Student this[int index]
{
get
{
if (index <= Count)
return Data[index - 1];
else
return null;
}
}
}
}
帮我优化下面的代码:qint32 press = channel/2048; QVector<double> temp(channel); if (press == 1){ for (int j = 0;j<16;j++){ for(int i = 0;i<128;i++){ temp<< receiveData[i+j136+2].toInt(nullptr,16); }} }else if (press > 1){ for (int j = 0;j<16;j++){ for(int i = 0;i<128;i++){ for (int k = 0;k<press;k++){ temp<<receiveData[i+j136+2].toInt(nullptr,16); } }} }else if (press < 1){ for (int j = 0;j<16;j++){ for(int i = 0;i<128press;i++){ double s = 0; for (int k = 0;k<int(1/press);k++){ s += receiveData[i+j136+2+k].toInt(nullptr,16); } temp<<s; }} } for (int i = 0 ;i<channel;i++) { scatterEX[i+firstchannel] += temp[i]; }
可以尝试将三个if语句合并为一个,避免重复的循环。同时,可以使用预处理器指令定义常量,以避免硬编码。最后,可以考虑使用并行化的方法来加速循环计算。优化后的代码如下:
```
#define BLOCK_SIZE 128
#define HEX_BASE 16
qint32 press = channel / 2048;
QVector<double> temp(channel);
#pragma omp parallel for
for (int j = 0; j < 16; j++) {
for (int i = 0; i < BLOCK_SIZE; i++) {
int index = i + j * BLOCK_SIZE + 2;
if (press == 1) {
temp << receiveData[index].toInt(nullptr, HEX_BASE);
} else if (press > 1) {
for (int k = 0; k < press; k++) {
temp << receiveData[index].toInt(nullptr, HEX_BASE);
}
} else if (press < 1) {
double s = 0;
for (int k = 0; k < int(1 / press); k++) {
s += receiveData[index + k].toInt(nullptr, HEX_BASE);
}
temp << s;
}
}
}
#pragma omp parallel for
for (int i = 0; i < channel; i++) {
scatterEX[i + firstchannel] += temp[i];
}
```
注意:如果原代码中的变量 `firstchannel` 是在其他地方定义的,需要在优化后的代码中进行相应的修改。