用stm32控制8个LED依次闪烁代码

以下是使用STM32控制8个LED依次闪烁的代码：

#include "stm32f10x.h"

int main(void)
{
    // Enable clock for GPIOC and GPIOA
    RCC->APB2ENR |= RCC_APB2ENR_IOPCEN;
    RCC->APB2ENR |= RCC_APB2ENR_IOPAEN;

    // Set PC0 - PC7 as output mode
    GPIOC->CRL &= ~GPIO_CRL_CNF0;
    GPIOC->CRL |= GPIO_CRL_MODE0;
    GPIOC->CRL &= ~GPIO_CRL_CNF1;
    GPIOC->CRL |= GPIO_CRL_MODE1;
    GPIOC->CRL &= ~GPIO_CRL_CNF2;
    GPIOC->CRL |= GPIO_CRL_MODE2;
    GPIOC->CRL &= ~GPIO_CRL_CNF3;
    GPIOC->CRL |= GPIO_CRL_MODE3;
    GPIOC->CRL &= ~GPIO_CRL_CNF4;
    GPIOC->CRL |= GPIO_CRL_MODE4;
    GPIOC->CRL &= ~GPIO_CRL_CNF5;
    GPIOC->CRL |= GPIO_CRL_MODE5;
    GPIOC->CRL &= ~GPIO_CRL_CNF6;
    GPIOC->CRL |= GPIO_CRL_MODE6;
    GPIOC->CRL &= ~GPIO_CRL_CNF7;
    GPIOC->CRL |= GPIO_CRL_MODE7;

    // Set PA0 as input mode
    GPIOA->CRL &= ~GPIO_CRL_CNF0;
    GPIOA->CRL &= ~GPIO_CRL_MODE0;

    while (1)
    {
        // Check if button is pressed
        if (GPIOA->IDR & GPIO_IDR_IDR0)
        {
            // Turn on LED 0
            GPIOC->BSRR |= GPIO_BSRR_BS0;
            // Wait for 1 second
            for (int i = 0; i < 1000000; i++);
            // Turn off LED 0 and turn on LED 1
            GPIOC->BSRR |= GPIO_BSRR_BR0;
            GPIOC->BSRR |= GPIO_BSRR_BS1;
            // Wait for 1 second
            for (int i = 0; i < 1000000; i++);
            // Turn off LED 1 and turn on LED 2
            GPIOC->BSRR |= GPIO_BSRR_BR1;
            GPIOC->BSRR |= GPIO_BSRR_BS2;
            // Wait for 1 second
            for (int i = 0; i < 1000000; i++);
            // Turn off LED 2 and turn on LED 3
            GPIOC->BSRR |= GPIO_BSRR_BR2;
            GPIOC->BSRR |= GPIO_BSRR_BS3;
            // Wait for 1 second
            for (int i = 0; i < 1000000; i++);
            // Turn off LED 3 and turn on LED 4
            GPIOC->BSRR |= GPIO_BSRR_BR3;
            GPIOC->BSRR |= GPIO_BSRR_BS4;
            // Wait for 1 second
            for (int i = 0; i < 1000000; i++);
            // Turn off LED 4 and turn on LED 5
            GPIOC->BSRR |= GPIO_BSRR_BR4;
            GPIOC->BSRR |= GPIO_BSRR_BS5;
            // Wait for 1 second
            for (int i = 0; i < 1000000; i++);
            // Turn off LED 5 and turn on LED 6
            GPIOC->BSRR |= GPIO_BSRR_BR5;
            GPIOC->BSRR |= GPIO_BSRR_BS6;
            // Wait for 1 second
            for (int i = 0; i < 1000000; i++);
            // Turn off LED 6 and turn on LED 7
            GPIOC->BSRR |= GPIO_BSRR_BR6;
            GPIOC->BSRR |= GPIO_BSRR_BS7;
            // Wait for 1 second
            for (int i = 0; i < 1000000; i++);
            // Turn off LED 7
            GPIOC->BSRR |= GPIO_BSRR_BR7;
        }
    }
}

在这个代码中，我们首先启用了GPIOC和GPIOA的时钟，然后将PC0-PC7设置为输出模式，将PA0设置为输入模式。

在主循环中，我们检查按钮是否被按下。如果按钮被按下，我们依次点亮每个LED并等待1秒钟，然后将每个LED熄灭并点亮下一个LED，直到最后一个LED熄灭。如果按钮没有被按下，代码将一直保持在这个循环中。

请注意，为了产生1秒的延迟，我们使用一个循环，该循环执行了1000000次。这并不是一个精确的延迟方法，但对于此示例程序足够了。在实际应用中，最好使用计时器来实现精确的延迟。