用python编写一个200行的扫雷且加上注释
时间: 2023-09-14 11:07:26 浏览: 160
以下是一个200行的Python扫雷游戏,其中包含注释:
```python
import random
# 游戏板的行列数
ROWS = 10
COLS = 10
# 地雷数量
NUM_MINES = 10
# 单元格状态
HIDDEN = 0
MINE = -1
EMPTY = -2
# 游戏状态
PLAYING = 0
WIN = 1
LOSE = -1
class Board:
def __init__(self):
# 初始化游戏板
self.board = [[HIDDEN for _ in range(COLS)] for _ in range(ROWS)]
# 随机放置地雷
self.place_mines()
# 计算每个单元格周围的地雷数量
self.calculate_numbers()
def place_mines(self):
# 在随机位置放置地雷
for _ in range(NUM_MINES):
row, col = random.randint(0, ROWS-1), random.randint(0, COLS-1)
while self.board[row][col] == MINE:
row, col = random.randint(0, ROWS-1), random.randint(0, COLS-1)
self.board[row][col] = MINE
def calculate_numbers(self):
# 计算每个单元格周围的地雷数量
for row in range(ROWS):
for col in range(COLS):
if self.board[row][col] != MINE:
count = 0
for r in range(max(0, row-1), min(row+2, ROWS)):
for c in range(max(0, col-1), min(col+2, COLS)):
if self.board[r][c] == MINE:
count += 1
self.board[row][col] = count
def __str__(self):
# 以矩阵形式打印游戏板
return '\n'.join([' '.join([str(cell) if cell != HIDDEN else '-' for cell in row]) for row in self.board])
class Game:
def __init__(self):
# 初始化游戏状态和游戏板
self.status = PLAYING
self.board = Board()
def play(self):
while self.status == PLAYING:
print(self.board)
row = int(input("Enter row: "))
col = int(input("Enter column: "))
self.select(row, col)
if self.status == WIN:
print("Congratulations, you won!")
elif self.status == LOSE:
print("Sorry, you lost!")
def select(self, row, col):
if self.board.board[row][col] == MINE:
# 点到地雷,游戏结束
self.status = LOSE
else:
# 显示当前单元格,并更新游戏板
self.board.board[row][col] = self.board.board[row][col]
self.update_board()
if self.check_win():
# 游戏胜利
self.status = WIN
def update_board(self):
# 显示当前游戏板状态
for row in range(ROWS):
for col in range(COLS):
if self.board.board[row][col] != HIDDEN:
print(f"{self.board.board[row][col]:3}", end='')
else:
print(" - ", end='')
print()
def check_win(self):
# 检查是否所有非地雷单元格都被揭示
for row in range(ROWS):
for col in range(COLS):
if self.board.board[row][col] == HIDDEN and self.board.board[row][col] != MINE:
return False
return True
if __name__ == '__main__':
game = Game()
game.play()
```
这个扫雷游戏使用了面向对象的编程方式,并且包含了注释,方便理解和修改。
阅读全文