C代码用斐波那契数列输出前10个数
时间: 2024-03-21 20:39:59 浏览: 13
以下是输出斐波那契数列前10个数的C代码:
```
#include <stdio.h>
int main() {
int n1 = 0, n2 = 1, nextNum, i;
printf("斐波那契数列前10个数为: ");
for (i = 1; i <= 10; ++i) {
printf("%d ", n1);
nextNum = n1 + n2;
n1 = n2;
n2 = nextNum;
}
return 0;
}
```
运行结果如下:
```
斐波那契数列前10个数为: 0 1 1 2 3 5 8 13 21 34
```