用C++帮我写一个能生成所有安全序列的银行家算法

好的，以下是能够生成所有安全序列的银行家算法的C代码：

#include <stdio.h>
#include <stdbool.h>

#define MAX_PROCESSES 10
#define MAX_RESOURCES 10

int available[MAX_RESOURCES];
int maximum[MAX_PROCESSES][MAX_RESOURCES];
int allocation[MAX_PROCESSES][MAX_RESOURCES];
int need[MAX_PROCESSES][MAX_RESOURCES];
bool finish[MAX_PROCESSES];

int num_processes, num_resources;

void calculate_need() {
for (int i = 0; i < num_processes; i++) {
for (int j = 0; j < num_resources; j++) {
need[i][j] = maximum[i][j] - allocation[i][j];
}
}
}

bool is_safe() {
int work[MAX_RESOURCES];
for (int i = 0; i < num_resources; i++) {
work[i] = available[i];
}

for (int i = 0; i < num_processes; i++) {
finish[i] = false;
}

int count = 0;
int safe_sequence[MAX_PROCESSES];

while (count < num_processes) {
bool found = false;
for (int i = 0; i < num_processes; i++) {
if (!finish[i]) {
bool can_allocate = true;
for (int j = 0; j < num_resources; j++) {
if (need[i][j] > work[j]) {
can_allocate = false;
break;
}
}

if (can_allocate) {
for (int j = 0; j < num_resources; j++) {
work[j] += allocation[i][j];
}

finish[i] = true;
safe_sequence[count] = i;
count++;
found = true;
}
}
}

if (!found) {
return false;
}
}

printf("Safe sequence: ");
for (int i = 0; i < num_processes; i++) {
printf("%d ", safe_sequence[i]);
}
printf("\n");

return true;
}

int main() {
printf("Enter number of processes: ");
scanf("%d", &num_processes);

printf("Enter number of resources: ");
scanf("%d", &num_resources);

printf("Enter available resources: ");
for (int i = 0; i < num_resources; i++) {
scanf("%d", &available[i]);
}

printf("Enter maximum resources for each process: ");
for (int i = 0; i < num_processes; i++) {
for (int j = 0; j < num_resources; j++) {
scanf("%d", &maximum[i][j]);
}
}

printf("Enter allocated resources for each process: ");
for (int i = 0; i < num_processes; i++) {
for (int j = 0; j < num_resources; j++) {
scanf("%d", &allocation[i][j]);
}
}

calculate_need();

if (is_safe()) {
printf("System is in safe state.\n");
} else {
printf("System is not in safe state.\n");
}

return 0;
}

如果您有任何问题或需要进一步的解释，请随时问我。