用vhdl语言实现以下流程:书写一个彩灯控制器,先让8盏灯全灭,然后依次点亮,后让8盏灯全亮,然后依次熄灭,最后让8盏灯全亮全灭,全亮全灭,全亮全灭,全亮全灭
时间: 2023-10-09 21:10:11 浏览: 155
基于VHDL实现多路彩灯控制器设计应用
好的,以下是一个实现方案:
```vhdl
entity led_controller is
port (
clk : in std_logic; -- 时钟信号
rst : in std_logic; -- 复位信号
led : out std_logic_vector(7 downto 0) -- 控制8盏灯的信号
);
end entity;
architecture rtl of led_controller is
signal count : unsigned(2 downto 0) := (others => '0'); -- 计数器,用于延时
signal state : std_logic_vector(5 downto 0) := "000000"; -- 状态机状态
begin
process (clk)
begin
if rising_edge(clk) then
if rst = '1' then
-- 复位状态
count <= (others => '0');
state <= "000000";
led <= (others => '0');
else
-- 根据状态机状态控制灯的状态
case state is
when "000000" =>
-- 全灭状态
if count = 7 then
count <= (others => '0');
state <= "000001";
else
count <= count + 1;
end if;
led <= (others => '0');
when "000001" =>
-- 依次点亮
if count = 7 then
count <= (others => '0');
state <= "000010";
else
count <= count + 1;
end if;
led(count) <= '1';
when "000010" =>
-- 全亮状态
if count = 7 then
count <= (others => '0');
state <= "000011";
else
count <= count + 1;
end if;
led <= (others => '1');
when "000011" =>
-- 依次熄灭
if count = 7 then
count <= (others => '0');
state <= "000100";
else
count <= count + 1;
end if;
led(count) <= '0';
when "000100" =>
-- 全亮状态
if count = 7 then
count <= (others => '0');
state <= "000101";
else
count <= count + 1;
end if;
led <= (others => '1');
when "000101" =>
-- 依次熄灭
if count = 7 then
count <= (others => '0');
state <= "000110";
else
count <= count + 1;
end if;
led(count) <= '0';
when "000110" =>
-- 全亮全灭
if count = 7 then
count <= (others => '0');
state <= "000111";
else
count <= count + 1;
end if;
led <= (others => '1');
when "000111" =>
-- 全亮全灭
if count = 7 then
count <= (others => '0');
state <= "001000";
else
count <= count + 1;
end if;
led <= not led;
when "001000" =>
-- 全亮全灭
if count = 7 then
count <= (others => '0');
state <= "001001";
else
count <= count + 1;
end if;
led <= (others => '1');
when "001001" =>
-- 全亮全灭
if count = 7 then
count <= (others => '0');
state <= "001010";
else
count <= count + 1;
end if;
led <= not led;
when "001010" =>
-- 全亮全灭
if count = 7 then
count <= (others => '0');
state <= "001011";
else
count <= count + 1;
end if;
led <= (others => '1');
when "001011" =>
-- 全亮全灭
if count = 7 then
count <= (others => '0');
state <= "000001";
else
count <= count + 1;
end if;
led <= not led;
when others =>
null;
end case;
end if;
end if;
end process;
end architecture;
```
这个控制器也是一个状态机,但是状态更多,实现了全亮全灭的效果。控制器的状态机状态变化和前面的实现方案类似,但是在状态 "000110" 到 "001011" 中,控制器会让灯在全亮和全灭的状态之间切换,实现全亮全灭的效果。在状态 "001011" 中,控制器会回到状态 "000001",重新开始循环。这样控制器就会不断循环地让8盏灯全灭、依次点亮、全亮、依次熄灭、全亮全灭,循环四次后重新开始。
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