考勤记录的添加、修改、删除等操作c++

以下是一个简单的考勤记录管理程序，包含添加、修改和删除操作：

#include <iostream>
#include <string>
#include <vector>

using namespace std;

struct Record {
    string name;        // 姓名
    int id;             // 学号
    int attendance;     // 出勤次数
};

vector<Record> records; // 存储所有考勤记录的数组

// 添加一条考勤记录
void addRecord() {
    Record r;
    cout << "请输入姓名：";
    cin >> r.name;
    cout << "请输入学号：";
    cin >> r.id;
    cout << "请输入出勤次数：";
    cin >> r.attendance;
    records.push_back(r);
    cout << "考勤记录已添加" << endl;
}

// 修改一条考勤记录
void modifyRecord() {
    int id;
    cout << "请输入要修改的学号：";
    cin >> id;
    for (int i = 0; i < records.size(); i++) {
        if (records[i].id == id) {
            cout << "请输入新的姓名：";
            cin >> records[i].name;
            cout << "请输入新的出勤次数：";
            cin >> records[i].attendance;
            cout << "考勤记录已修改" << endl;
            return;
        }
    }
    cout << "未找到该学号的考勤记录" << endl;
}

// 删除一条考勤记录
void deleteRecord() {
    int id;
    cout << "请输入要删除的学号：";
    cin >> id;
    for (int i = 0; i < records.size(); i++) {
        if (records[i].id == id) {
            records.erase(records.begin() + i);
            cout << "考勤记录已删除" << endl;
            return;
        }
    }
    cout << "未找到该学号的考勤记录" << endl;
}

// 显示所有考勤记录
void showRecords() {
    cout << "姓名\t学号\t出勤次数" << endl;
    for (int i = 0; i < records.size(); i++) {
        cout << records[i].name << "\t" << records[i].id << "\t" << records[i].attendance << endl;
    }
}

int main() {
    while (true) {
        cout << "请选择操作：" << endl;
        cout << "1. 添加考勤记录" << endl;
        cout << "2. 修改考勤记录" << endl;
        cout << "3. 删除考勤记录" << endl;
        cout << "4. 显示所有考勤记录" << endl;
        cout << "5. 退出程序" << endl;
        int choice;
        cin >> choice;
        switch (choice) {
            case 1:
                addRecord();
                break;
            case 2:
                modifyRecord();
                break;
            case 3:
                deleteRecord();
                break;
            case 4:
                showRecords();
                break;
            case 5:
                return 0;
            default:
                cout << "无效的选项" << endl;
                break;
        }
    }
}

注意，这只是一个简单的示例程序，没有做输入合法性检查等处理。在实际应用中，需要根据具体情况进行扩展和优化。