a={'Mike':90,'Mark':91,'Amy':89} sorted_scores = sorted(a.items(), key=lambda x: (x[0], -x[1])) print(sorted_scores)解释并输出

这段代码定义了一个字典a，其中包含三个键值对，键为'Mike'，'Mark'和'Amy'，对应的值分别为90，91和89。

接下来，代码使用sorted()函数对字典a进行排序。排序的关键是lambda表达式，即对每个键值对，按照键的字母顺序升序排序，对于相同键的情况，按照值的大小降序排序。

最后，将排序结果打印输出。输出结果为：

[('Amy', 89), ('Mark', 91), ('Mike', 90)]

相关问题

a={'Mike':90,'Mark':91,'Amy':89} sorted_scores = sorted(a.items(), key=lambda x: (x[0], -x[1])) print(sorted_scores)

The output of the code will be:

[('Amy', 89), ('Mark', 91), ('Mike', 90)]

Explanation:

- The dictionary 'a' contains three key-value pairs representing the scores of three students.
- The 'sorted' function is used to sort the dictionary by the keys and the values.
- The 'items' method is used to convert the dictionary into a list of tuples where each tuple contains the key-value pair.
- The 'key' argument of the 'sorted' function is set to a lambda function that takes a tuple as input and returns a tuple of two values. The first value is the key itself (i.e., the name of the student), and the second value is the negative of the score. The negative is used to sort the scores in descending order.
- The resulting list of tuples is stored in the 'sorted_scores' variable and printed to the console.

a={'Mike':90,'Mark':91,'Amy':89} sorted_scores = sorted(a.items(), key=lambda x: (x[0], -x[1]))

This code sorts the dictionary 'a' by the keys in ascending order and the values in descending order. The result is a list of tuples containing the key-value pairs in the sorted order.

For example, if we print the sorted_scores list, we will get:

[('Amy', 89), ('Mark', 91), ('Mike', 90)]

This means that the key 'Amy' has the lowest score (89), followed by 'Mark' with a score of 91, and 'Mike' with a score of 90. If two keys have the same score, they are sorted alphabetically.