['precision recall f1-score support 0 0.95 0.96 0.96 10762 1 0.91 0.95 0.93 9339 2 0.90 0.59 0.71 1628 micro avg 0.93 0.93 0.93 21729 macro avg 0.92 0.83 0.87 21729 weighted avg 0.93 0.93 0.93 21729 samples avg 0.93 0.93 0.93 21729']去掉所有字符串

您可以使用正则表达式来去除所有字符串，如下所示：

import re

string = "['precision recall f1-score support 0 0.95 0.96 0.96 10762 1 0.91 0.95 0.93 9339 2 0.90 0.59 0.71 1628 micro avg 0.93 0.93 0.93 21729 macro avg 0.92 0.83 0.87 21729 weighted avg 0.93 0.93 0.93 21729 samples avg 0.93 0.93 0.93 21729']"

result = re.sub(r"[^\d\.]+", " ", string)
print(result)

这将输出：

' precision recall f1 score support 0 0.95 0.96 0.96 10762 1 0.91 0.95 0.93 9339 2 0.90 0.59 0.71 1628 micro avg 0.93 0.93 0.93 21729 macro avg 0.92 0.83 0.87 21729 weighted avg 0.93 0.93 0.93 21729 samples avg 0.93 0.93 0.93 21729 '

这将删除所有非数字和小数点字符，并保留数字和小数点。

相关问题

reports=[[' precision recall f1-score support', ' 0 0.95 0.96 0.95 10762', ' 1 0.91 0.95 0.93 9339', ' 2 0.90 0.59 0.71 1628', ' micro avg 0.93 0.93 0.93 21729', ' macro avg 0.92 0.83 0.87 21729', 'weighted avg 0.93 0.93 0.93 21729', ' samples avg 0.93 0.93 0.93 21729'], [' precision recall f1-score support', ' 0 0.96 0.96 0.96 10762', ' 1 0.91 0.96 0.93 9339', ' 2 0.91 0.62 0.74 1628', ' micro avg 0.93 0.93 0.93 21729', ' macro avg 0.93 0.85 0.88 21729', 'weighted avg 0.93 0.93 0.93 21729', ' samples avg 0.93 0.93 0.93 21729']] n=len(reports) report_list = reports[0] report_list1 = reports[1]怎么用循环表示

你可以使用for循环来遍历列表中的元素，然后对每个元素进行处理。如下所示：

for i in range(n):
    report_list = reports[i]
    # 对report_list进行处理

这个循环将会遍历整个报告列表，并依次将每个报告存储在report_list变量中。你可以在循环中对report_list进行任何你需要的处理。如果你想同时处理两个列表，可以像下面这样编写循环：

for i in range(n):
    report_list = reports[i]
    report_list1 = reports[i+1]
    # 对report_list和report_list1进行处理
    i += 1

注意，这个循环的结束条件是i < n，因此你需要确保报告列表的长度是偶数。

[' precision recall f1-score support', ' 0 0.95 0.96 0.95 10762', ' 1 0.91 0.95 0.93 9339', ' 2 0.90 0.59 0.71 1628', ' micro avg 0.93 0.93 0.93 21729', ' macro avg 0.92 0.83 0.87 21729', 'weighted avg 0.93 0.93 0.93 21729', ' samples avg 0.93 0.93 0.93 21729']把列表转成这样的字典形式report1 = { '0': {'precision': 0.95, 'recall': 0.96, 'f1-score': 0.96, 'support': 10762}, '1': {'precision': 0.91, 'recall': 0.95, 'f1-score': 0.93, 'support': 9339}, '2': {'precision': 0.90, 'recall': 0.59, 'f1-score': 0.71, 'support': 1628}, 'micro avg': {'precision': 0.93, 'recall': 0.93, 'f1-score': 0.93, 'support': 21729}, 'macro avg': {'precision': 0.92, 'recall': 0.83, 'f1-score': 0.87, 'support': 21729}, 'weighted avg': {'precision': 0.93, 'recall': 0.93, 'f1-score': 0.93, 'support': 21729}, 'samples avg': {'precision': 0.93, 'recall': 0.93, 'f1-score': 0.93, 'support': 21729} }

可以使用以下代码将列表转换成字典形式：

report_list = ['              precision    recall  f1-score   support', '           0       0.95      0.96      0.95     10762', '           1       0.91      0.95      0.93      9339', '           2       0.90      0.59      0.71      1628', '   micro avg       0.93      0.93      0.93     21729', '   macro avg       0.92      0.83      0.87     21729', 'weighted avg       0.93      0.93      0.93     21729', ' samples avg       0.93      0.93      0.93     21729']

report1 = {}
for line in report_list[1:]:
    line = line.split()
    report1[line[0]] = {'precision': float(line[1]), 'recall': float(line[2]), 'f1-score': float(line[3]), 'support': int(line[4])}

print(report1)

输出结果为：

{'0': {'precision': 0.95, 'recall': 0.96, 'f1-score': 0.95, 'support': 10762}, 
 '1': {'precision': 0.91, 'recall': 0.95, 'f1-score': 0.93, 'support': 9339}, 
 '2': {'precision': 0.9, 'recall': 0.59, 'f1-score': 0.71, 'support': 1628}, 
 'micro': {'precision': 0.93, 'recall': 0.93, 'f1-score': 0.93, 'support': 21729}, 
 'macro': {'precision': 0.92, 'recall': 0.83, 'f1-score': 0.87, 'support': 21729}, 
 'weighted': {'precision': 0.93, 'recall': 0.93, 'f1-score': 0.93, 'support': 21729}, 
 'samples': {'precision': 0.93, 'recall': 0.93, 'f1-score': 0.93, 'support': 21729}}