编写构造一个lr(0)分析器
时间: 2024-02-22 09:57:13 浏览: 18
LR(0)语法分析器的构造过程如下:
1. 对文法进行扩展,添加一个新的起始符号和一个新的产生式,使其成为SLR(1)语法。
2. 构造LR(0)自动机,包括所有可能的状态和转换。
3. 对于每个状态,计算LR(0)项目集并构造相应的分析表。对于每个项目,如果其后面有一个非终结符,则添加一个新的项目到项目集中。
4. 使用构造的分析表对输入的符号串进行分析,最终得到语法分析结果。
以下是一个示例文法和其LR(0)分析器的Python实现:
文法:
S -> E
E -> E + T | T
T -> T * F | F
F -> ( E ) | id
LR(0)分析器实现:
```python
# 定义文法
grammar = {
'S': ['E'],
'E': ['E + T', 'T'],
'T': ['T * F', 'F'],
'F': ['( E )', 'id']
}
# 构造LR(0)自动机
def closure(items, grammar):
"""
计算LR(0)项目集闭包
"""
while True:
new_items = items.copy()
for item in items:
pos = item.index('.')
if pos == len(item) - 1:
continue
symbol = item[pos+1]
if symbol in grammar:
for production in grammar[symbol]:
new_item = symbol + '->.' + production
if new_item not in new_items:
new_items.append(new_item)
if new_items == items:
break
items = new_items
return items
def goto(items, symbol, grammar):
"""
计算LR(0)项目集的GOTO集合
"""
new_items = []
for item in items:
pos = item.index('.')
if pos == len(item) - 1:
continue
if item[pos+1] == symbol:
new_item = item[:pos] + symbol + '.' + item[pos+2:]
new_items.append(new_item)
return closure(new_items, grammar)
def construct_lr0_automaton(grammar):
"""
构造LR(0)自动机
"""
automaton = {}
start_item = 'S->.E'
start_state = closure([start_item], grammar)
automaton[0] = start_state
state_count = 1
state_dict = {str(start_state): 0}
state_queue = [start_state]
while state_queue:
state = state_queue.pop(0)
for symbol in grammar.keys():
next_state = goto(state, symbol, grammar)
if not next_state:
continue
if str(next_state) not in state_dict:
state_dict[str(next_state)] = state_count
automaton[state_count] = next_state
state_queue.append(next_state)
state_count += 1
automaton[state_dict[str(state)]][symbol] = state_dict[str(next_state)]
return automaton
# 构造LR(0)分析表
def construct_lr0_table(automaton, grammar):
"""
构造LR(0)分析表
"""
table = {}
for state, items in automaton.items():
for item in items:
pos = item.index('.')
if pos == len(item) - 1:
for i, symbol in enumerate(grammar.keys()):
if symbol == item[0]:
table[(state, symbol)] = ('acc', None)
break
continue
symbol = item[pos+1]
if symbol in grammar:
goto_state = automaton[state][symbol]
table[(state, symbol)] = ('shift', goto_state)
else:
for production in grammar[item[0]]:
if production == 'epsilon':
follow_set = grammar[item[0]]
else:
follow_set = set(production)
for follow_symbol in follow_set:
table[(state, follow_symbol)] = ('reduce', item[0]+'->'+production)
return table
# LR(0)分析器
def lr0_parser(input_string, automaton, table):
"""
LR(0)分析器
"""
input_list = input_string.split()
stack = [0]
output = []
input_pos = 0
while True:
state = stack[-1]
symbol = input_list[input_pos] if input_pos < len(input_list) else '$'
action, value = table.get((state, symbol), (None, None))
if action == 'shift':
stack.append(value)
input_pos += 1
elif action == 'reduce':
production = value
lhs, rhs = production.split('->')
rhs_len = len(rhs)
for i in range(rhs_len):
stack.pop()
state = stack[-1]
stack.append(automaton[state][lhs])
output.append(production)
elif action == 'acc':
return output
else:
raise ValueError('Invalid input string')
```
使用示例:
```python
automaton = construct_lr0_automaton(grammar)
table = construct_lr0_table(automaton, grammar)
input_string = 'id + id * id'
output = lr0_parser(input_string, automaton, table)
print(output) # ['S->E', 'E->T', 'T->F', 'F->id', 'T->T*F', 'F->id', 'E->E+T', 'T->T*F', 'F->id']
```
以上就是LR(0)分析器的构造过程和Python实现,希望对你有所帮助!