编写代码 ServletRequestAttributes 响应json数据

好的，您想知道如何在Java中使用ServletRequestAttributes来响应JSON数据，正确吗？

首先，您需要导入以下依赖项：

<dependency>
    <groupId>com.fasterxml.jackson.core</groupId>
    <artifactId>jackson-databind</artifactId>
    <version>2.10.0</version>
</dependency>

然后，您可以使用以下代码片段：

import com.fasterxml.jackson.databind.ObjectMapper;
import org.springframework.web.context.request.RequestContextHolder;
import org.springframework.web.context.request.ServletRequestAttributes;

import javax.servlet.http.HttpServletResponse;
import java.io.IOException;
import java.io.PrintWriter;

public class JsonUtil {

    public static void writeJson(Object object) throws IOException {
        ServletRequestAttributes attributes = (ServletRequestAttributes) RequestContextHolder.getRequestAttributes();
        HttpServletResponse response = attributes.getResponse();
        response.setCharacterEncoding("UTF-8");
        response.setContentType("application/json;charset=utf-8");
        PrintWriter out = response.getWriter();
        ObjectMapper mapper = new ObjectMapper();
        out.write(mapper.writeValueAsString(object));
        out.flush();
        out.close();
    }
}

这个实用程序类将ServletRequestAttributes转换为HttpServletResponse对象，并使用ObjectMapper将对象转换为JSON格式。最后，将响应输出到输出流中。

希望这可以解决您的问题！