C语言例如:字符串"league of legend"包含了"end",所以"end"是"league of legend"的子串。 同理,"leg"也是"league of legend"的子串。 但"lend"不是"league of legend"的子串,虽然字母l、e、n、d均出现在"league of legend"中。 要求:输入两个字符串S1和S2,S1和S2的长度大于0且小于100,统计S2在S1中出现的次数。 例如,输入: blah/blah/blah/ blah/blah 输出: 1
时间: 2023-07-02 17:16:32 浏览: 59
好的,以下是同样功能的 C 语言代码实现:
```c
#include <stdio.h>
#include <string.h>
#define MAX_LEN 100
int main() {
char S1[MAX_LEN+1], S2[MAX_LEN+1];
int len1, len2, count = 0;
// 读入 S1 和 S2
scanf("%s%s", S1, S2);
len1 = strlen(S1);
len2 = strlen(S2);
// 在 S1 中查找 S2
for (int i = 0; i <= len1 - len2; i++) {
if (strncmp(S1 + i, S2, len2) == 0) {
count++;
}
}
// 输出结果
printf("%d\n", count);
return 0;
}
```
具体实现思路与 Python 代码类似,同样是在 S1 中遍历每一个长度为 S2 的子串,依次比较是否与 S2 相等,如果相等则计数器加一。需要注意的是,在 C 语言中需要使用 `strncmp` 函数进行字符串比较,以避免出现字符串越界的问题。
相关问题
例如:字符串"league of legend"包含了"end",所以"end"是"league of legend"的子串。 同理,"leg"也是"league of legend"的子串。 但"lend"不是"league of legend"的子串,虽然字母l、e、n、d均出现在"league of legend"中。 要求:输入两个字符串S1和S2,S1和S2的长度大于0且小于100,统计S2在S1中出现的次数。 例如,输入: blah/blah/blah/ blah/blah 输出: 1
好的,根据您的要求,我能给出以下 Python 代码实现:
```
S1 = input().strip()
S2 = input().strip()
count = 0
for i in range(len(S1) - len(S2) + 1):
if S1[i:i+len(S2)] == S2:
count += 1
print(count)
```
具体实现思路是,在 S1 中遍历每一个长度为 S2 的子串,依次比较是否与 S2 相等,如果相等则计数器加一,最后输出结果即可。
League of Legends Rookie
As an AI language model, I do not have personal experiences or emotions, but here is a description of what a League of Legends rookie might go through:
A League of Legends rookie is a new player who is just starting to explore the game. They may feel overwhelmed by the vast amount of information, champions, and strategies to learn. As they start playing, they will encounter different game modes such as normal games, ranked games, and ARAM, which they will need to understand and master.
Rookies may struggle with understanding the game's mechanics, such as last-hitting minions for gold, positioning, and map awareness. They may also find it challenging to choose which champion to play, as there are over 150 different characters in the game, each with its unique abilities and playstyle.
As they play more games, rookies will start to learn and adapt to the game's mechanics and strategies. They may seek advice from more experienced players, watch tutorial videos, and read guides to improve their gameplay. They will also start to understand the importance of teamwork, communication, and decision-making in League of Legends.
Overall, being a League of Legends rookie can be challenging, but it is also an exciting and rewarding experience as they grow and improve their skills.