def hys(nums, k, subset): res = [] if sum(subset) == k and 0 not in subset: res.append(subset) elif sum(subset) < k and 0 not in subset: for i in range(len(nums)): if nums[i] not in subset: new_subset = subset + [nums[i]] new_nums = nums[i+1:] res += hys(new_nums, k, new_subset) return res while True: try: n, k = map(int, input().split()) nums = list(map(int, input().split())) if k==0: if 0 in nums: print("YES") print("0") else: print("NO") else: for i in nums: if i==0: nums.remove(i) res = hys(nums, k, []) if res: print("YES") for subset in res: print(" ".join(str(x) for x in subset )) else: print("NO") except: break请问怎么改进代码使若有多个子集满足条件时，只输出出现的第一个子集

可以在找到第一个满足条件的子集后，添加一个 `break` 语句，让程序跳出循环，不再继续查找其他满足条件的子集。具体地，在代码中可以修改为：

if res:
    print("YES")
    for subset in res:
        print(" ".join(str(x) for x in subset ))
        break  # 添加 break 语句
else:
    print("NO")

这样就可以保证只输出第一个满足条件的子集了。