把这段代码从C语言改为C++语言 int s1, s2, len, terminal[m*2]; char ch; for(i = 0; i < m; ++i) { scanf("%d", &s1); s1--; terminal[i*2] = s1; ch = getchar(); while(ch != '\n') { scanf("%d %d", &len, &s2); s2--; if(D[s1][s2] == -1 || D[s1][s2] > len) { D[s1][s2] = len; D[s2][s1] = D[s1][s2]; } s1 = s2; ch = getchar(); } terminal[i*2 + 1] = s1; }

在C++中，可以使用cin和cout代替scanf和printf函数。以下是将此代码转换为C++的方式：

int s1, s2, len, terminal[m*2];
char ch;
for(int i = 0; i < m; ++i)
{
    cin >> s1;
    s1--;
    terminal[i*2] = s1;
    ch = getchar();
    while(ch != '\n')
    {
        cin >> len >> s2;
        s2--;
        if(D[s1][s2] == -1 || D[s1][s2] > len)
        {
            D[s1][s2] = len;
            D[s2][s1] = D[s1][s2];
        }
        s1 = s2;
        ch = getchar();
    }
    terminal[i*2 + 1] = s1;
}

请注意，由于在C++中，数组的大小必须在编译时确定，因此可以考虑使用vector代替数组。以下是使用vector的代码：

int s1, s2, len;
char ch;
vector<int> terminal(m*2);
for(int i = 0; i < m; ++i)
{
    cin >> s1;
    s1--;
    terminal[i*2] = s1;
    ch = getchar();
    while(ch != '\n')
    {
        cin >> len >> s2;
        s2--;
        if(D[s1][s2] == -1 || D[s1][s2] > len)
        {
            D[s1][s2] = len;
            D[s2][s1] = D[s1][s2];
        }
        s1 = s2;
        ch = getchar();
    }
    terminal[i*2 + 1] = s1;
}