df = pd.DataFrame({'key1' : ['a','a','c','d','a'], 'key2' : ['yes', 'no', 'yes', 'yes', 'no'], 'data1' : np.random.randn(5), 'data2' : np.random.randn(5)}) grouped = df['data1'].groupby(df['key1']) print(grouped.size()) print(grouped.mean()) groupk1 = df.groupby('key2').mean() print(groupk1) wlist = ['w','w','y','w','y'] df.groupby(wlist).sum() df1 = pd.DataFrame(np.random.normal(size = (6,5)),index = ['a','b','c','A','B','c']) print("数据为:\n",df) wdict = {'a':'one','A':'one','b':'two','B':'two','c':'three'} print("分组汇总后的结果为:\n",df.groupby(wdict).sum())检查代码错误
时间: 2023-08-20 14:39:12 浏览: 47
这段代码的语法没有错误,但是在输出结果时可能存在一些问题。具体来说,下面代码中最后输出的结果,应该是对 df1 进行分组汇总后的结果,而不是对 df 进行分组汇总的结果。
正确的代码如下所示(已将最后一行修改为对 df1 进行分组汇总的结果):
```python
import pandas as pd
import numpy as np
df = pd.DataFrame({'key1' : ['a','a','c','d','a'],
'key2' : ['yes', 'no', 'yes', 'yes', 'no'],
'data1' : np.random.randn(5),
'data2' : np.random.randn(5)})
grouped = df['data1'].groupby(df['key1'])
print(grouped.size())
print(grouped.mean())
groupk1 = df.groupby('key2').mean()
print(groupk1)
wlist = ['w','w','y','w','y']
print(df.groupby(wlist).sum())
df1 = pd.DataFrame(np.random.normal(size=(6,5)), index=['a','b','c','A','B','c'])
print("数据为:\n", df1)
wdict = {'a':'one','A':'one','b':'two','B':'two','c':'three'}
print("分组汇总后的结果为:\n", df1.groupby(wdict).sum())
```
希望这次回答能够帮到您!