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时间: 2024-05-15 15:19:56 浏览: 47
这是一个关于编程的问题,我可以帮助您回答。以下是一个示例代码:
```c++
#include <stdio.h>
#include <stdlib.h>
void rotate_square(int **square, int size) {
// transpose the square
for (int i = 0; i < size; i++) {
for (int j = i; j < size; j++) {
int tmp = square[i][j];
square[i][j] = square[j][i];
square[j][i] = tmp;
}
}
// reverse each row
for (int i = 0; i < size; i++) {
for (int j = 0; j < size / 2; j++) {
int tmp = square[i][j];
square[i][j] = square[i][size - 1 - j];
square[i][size - 1 - j] = tmp;
}
}
}
void print_square(int **square, int size) {
for (int i = 0; i < size; i++) {
for (int j = 0; j < size; j++) {
printf("%d ", square[i][j]);
}
printf("\n");
}
}
void create_magic_square(int **square, int size) {
int row = 0, col = size / 2;
for (int i = 1; i <= size*size; i++) {
square[row][col] = i;
int next_row = row == 0 ? size - 1 : row - 1;
int next_col = col == size - 1 ? 0 : col + 1;
if (square[next_row][next_col]) {
row = (row + 1) % size;
} else {
row = next_row;
col = next_col;
}
}
}
int main() {
int size;
printf("Enter the size of the magic square (odd number): ");
scanf("%d", &size);
if (size % 2 == 0) {
printf("Invalid size!\n");
return 1;
}
int **square = (int**) malloc(size * sizeof(int*));
for (int i = 0; i < size; i++) {
square[i] = (int*) malloc(size * sizeof(int));
}
create_magic_square(square, size);
printf("Original square:\n");
print_square(square, size);
printf("Rotated square:\n");
rotate_square(square, size);
print_square(square, size);
for (int i = 0; i < size; i++) {
free(square[i]);
}
free(square);
return 0;
}
```
这个程序使用了二维数组来存储奇数阶幻方。程序会提示用户输入幻方的阶数,然后使用“魔术算法”来生成幻方。接下来,程序会输出原始幻方和向右旋转90度后的幻方。
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