import java.util.HashMap; import java.util.Scanner; import java.util.TreeSet; public class Main { public static void main(String args[]) { Scanner sc = new Scanner(System.in); String[] name = {"Captain", "Priest", "Cook", "Doctor", "Engineer", "Hunter", "Gunner", "Navigator"}; HashMap<String, Integer> map = new HashMap<>(); map.put(sc.next(), 1); int n = sc.nextInt(); for (int i = 0; i < n; i++) { String s = sc.nextLine(); String ss = s.split(":")[0]; map.put(ss, 1); } TreeSet<String> t = new TreeSet<>(); for (int i = 0; i < 8; i++) { if (!map.containsKey(name[i])) t.add(name[i]); } if (t.size() == 0) System.out.println("Ready"); else { for (Object o : t) System.out.println(o); } } }

以下是将Java代码转换为C语言代码的示例，为了简化代码，该示例省略了输入和输出部分的具体实现，需要您根据实际情况进行适当修改：

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

#define NAME_SIZE 8

int main() {
    char name[NAME_SIZE][10] = {"Captain", "Priest", "Cook", "Doctor", "Engineer", "Hunter", "Gunner", "Navigator"};
    char input[100];
    int n = 0;
    scanf("%d", &n);
    getchar(); // 处理输入缓冲区残留的换行符
    int count = 0;
    int map[100] = {0};
    for (int i = 0; i < n; i++) {
        fgets(input, 100, stdin);
        char* p = strtok(input, ":");
        int index = -1;
        for (int j = 0; j < NAME_SIZE; j++) {
            if (strcmp(name[j], p) == 0) {
                index = j;
                break;
            }
        }
        if (index >= 0) {
            map[index] = 1;
            count++;
        }
    }
    for (int i = 0; i < NAME_SIZE; i++) {
        if (map[i] == 0) {
            printf("%s\n", name[i]);
        }
    }
    if (count == NAME_SIZE) {
        printf("Ready\n");
    }
    return 0;
}

需要注意的是，Java代码和C语言代码的语法和结构有很大的不同，因此在进行转换时需要仔细思考和分析，以确保转换后的代码逻辑正确、运行稳定。