Consider two 4-bit binary numbers A and B. Bits of A are a3, a2, a1, and a0, and bits of B are b3, b2, b1, and b0. A is greater than B if a3 is 1 and b3 is 0, but if a3 and b3 are the same, then if a2 is 1 and b2 is 0, we can determine that A is greater than B. This evaluation continues until a0 and b0 are considered. If a0 and b0 are equal then A and B are equal. Using discrete gates and Verilog gate primitives build a 4-bit comparator that generates a 1 on its GT output when its 4-bit input A is greater than its B input, and a 1 on its EQ output when A and B are equal. Use the generate statement and other Verilog iterative logic support structures. The code should be as simple as possible。
时间: 2023-12-22 10:02:52 浏览: 16
Here is a Verilog code for the 4-bit comparator that generates a 1 on its GT output when its 4-bit input A is greater than its B input, and a 1 on its EQ output when A and B are equal:
```
module comparator (
input [3:0] A,
input [3:0] B,
output GT,
output EQ
);
assign GT = 0;
assign EQ = 0;
generate
for (i = 3; i >= 0; i--) begin
if (A[i] > B[i]) begin
assign GT = 1;
assign EQ = 0;
break;
end else if (A[i] < B[i]) begin
assign GT = 0;
assign EQ = 0;
break;
end else begin
assign EQ = 1;
end
end
endgenerate
endmodule
```
The code uses a generate statement to iterate through the bits of A and B, comparing them one by one from the most significant bit (a3 and b3) to the least significant bit (a0 and b0). If A is greater than B, the GT output is set to 1 and the iteration is stopped. If A is less than B, the GT output is set to 0 and the iteration is stopped. If A and B are equal, the EQ output is set to 1 and the iteration continues to the next bit. Once all bits have been compared, the EQ output remains 1 if A and B are equal.