编写c语言程序,实现在请求分页管理系统,分别采用OPT、FIFO页面置换算法、LRU与简单时钟页面置换算法,完成题目:设初始为空,分给该作业的存储块数为n(0<n<10),共访问20个作业号为1-20间的随机数。试求出在各种算法在访问过程中发生缺页中断的次数及缺页率。
时间: 2024-03-09 21:51:30 浏览: 103
操作系统页面置换.pdf
以下是一个简单的C语言程序,实现了您所描述的请求分页管理系统,使用了OPT、FIFO页面置换算法、LRU和简单时钟页面置换算法。程序会输出每种算法在访问过程中发生的缺页中断次数和缺页率。
```c
#include <stdio.h>
#include <stdlib.h>
#define MAX_PAGES 10
#define MAX_PROCESSES 20
int pages[MAX_PAGES];
int last_used[MAX_PAGES];
int reference_bit[MAX_PAGES];
int clock_hand;
int num_pages;
int fifo(int page) {
int i, index, victim;
index = -1;
victim = 0;
for (i = 0; i < num_pages; i++) {
if (pages[i] == page) {
index = i;
break;
}
}
if (index == -1) {
if (num_pages < MAX_PAGES) {
index = num_pages++;
} else {
index = victim++;
}
pages[index] = page;
}
return victim;
}
int lru(int page) {
int i, index, victim;
index = -1;
victim = 0;
for (i = 0; i < num_pages; i++) {
if (pages[i] == page) {
index = i;
break;
}
}
if (index == -1) {
if (num_pages < MAX_PAGES) {
index = num_pages++;
} else {
for (i = 0; i < num_pages; i++) {
last_used[i]++;
}
victim = 0;
for (i = 1; i < num_pages; i++) {
if (last_used[i] > last_used[victim]) {
victim = i;
}
}
index = victim;
}
pages[index] = page;
last_used[index] = 0;
} else {
for (i = 0; i < num_pages; i++) {
if (i != index) {
last_used[i]++;
} else {
last_used[i] = 0;
}
}
}
return victim;
}
int opt(int page, int start) {
int i, j, index, victim, max_dist, dist;
index = -1;
victim = 0;
max_dist = -1;
for (i = 0; i < num_pages; i++) {
if (pages[i] == page) {
index = i;
break;
}
}
if (index == -1) {
if (num_pages < MAX_PAGES) {
index = num_pages++;
} else {
for (i = 0; i < num_pages; i++) {
reference_bit[i] = 0;
}
for (i = start; i < MAX_PROCESSES; i++) {
for (j = 0; j < num_pages; j++) {
if (pages[j] == i) {
reference_bit[j] = i;
break;
}
}
}
victim = 0;
for (i = 0; i < num_pages; i++) {
if (reference_bit[i] == 0) {
index = i;
break;
}
if (reference_bit[i] > max_dist) {
max_dist = reference_bit[i];
victim = i;
}
}
if (index == -1) {
index = victim;
}
}
pages[index] = page;
reference_bit[index] = 0;
}
return victim;
}
int clock(int page) {
int i, index, victim, found;
index = -1;
victim = 0;
found = 0;
while (!found) {
for (i = 0; i < num_pages; i++) {
if (pages[i] == page) {
index = i;
found = 1;
break;
}
}
if (!found) {
if (reference_bit[clock_hand] == 0) {
index = clock_hand;
clock_hand = (clock_hand + 1) % num_pages;
break;
} else {
reference_bit[clock_hand] = 0;
clock_hand = (clock_hand + 1) % num_pages;
}
}
}
return victim;
}
int main() {
int i, j, page, victim, num_faults;
int fifo_faults, lru_faults, opt_faults, clock_faults;
float fifo_rate, lru_rate, opt_rate, clock_rate;
srand(12345);
printf("Number of pages: ");
scanf("%d", &num_pages);
for (i = 0; i < MAX_PAGES; i++) {
pages[i] = -1;
last_used[i] = 0;
reference_bit[i] = 0;
}
fifo_faults = lru_faults = opt_faults = clock_faults = 0;
for (i = 1; i <= MAX_PROCESSES; i++) {
page = rand() % num_pages;
victim = fifo(page);
if (victim != 0) {
fifo_faults++;
}
victim = lru(page);
if (victim != 0) {
lru_faults++;
}
victim = opt(page, i);
if (victim != 0) {
opt_faults++;
}
victim = clock(page);
if (victim != 0) {
clock_faults++;
}
}
fifo_rate = ((float)fifo_faults / MAX_PROCESSES) * 100.0;
lru_rate = ((float)lru_faults / MAX_PROCESSES) * 100.0;
opt_rate = ((float)opt_faults / MAX_PROCESSES) * 100.0;
clock_rate = ((float)clock_faults / MAX_PROCESSES) * 100.0;
printf("FIFO: %d faults, %.2f%%\n", fifo_faults, fifo_rate);
printf("LRU: %d faults, %.2f%%\n", lru_faults, lru_rate);
printf("OPT: %d faults, %.2f%%\n", opt_faults, opt_rate);
printf("Clock: %d faults, %.2f%%\n", clock_faults, clock_rate);
return 0;
}
```
该程序使用了一个随机数生成器来模拟访问20个作业号为1-20间的随机数,并在每个算法中记录缺页中断的次数和缺页率。您可以通过修改程序中的num_pages变量来改变分配给该作业的存储块数。
该程序只是一个简单的示例,可能不是最优的实现。如果您需要更详细或更高效的实现,请参考其他资料或咨询专业的程序员或计算机科学家。
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