用链表输出数组num[]={1,2,3,4}

可以使用链表来输出数组 `num[]={1,2,3,4}`，以下是一个示例代码：

#include <stdio.h>
#include <stdlib.h>

// 定义链表节点
struct Node {
    int data;
    struct Node* next;
};

// 将数组转换为链表
struct Node* arrayToLinkedList(int arr[], int size) {
    struct Node* head = NULL;
    struct Node* temp = NULL;
    struct Node* current = NULL;

    for (int i = 0; i < size; i++) {
        temp = (struct Node*)malloc(sizeof(struct Node));
        temp->data = arr[i];
        temp->next = NULL;

        if (head == NULL) {
            head = temp;
        } else {
            current = head;
            while (current->next != NULL) {
                current = current->next;
            }
            current->next = temp;
        }
    }

    return head;
}

// 打印链表元素
void printLinkedList(struct Node* head) {
    struct Node* current = head;

    while (current != NULL) {
        printf("%d ", current->data);
        current = current->next;
    }
    printf("\n");
}

int main() {
    int num[] = {1, 2, 3, 4};
    int size = sizeof(num) / sizeof(num[0]);

    // 将数组转换为链表
    struct Node* head = arrayToLinkedList(num, size);

    // 打印链表元素
    printLinkedList(head);

    return 0;
}

输出结果：

1 2 3 4

以上代码将数组 `num` 转换为链表，并按顺序打印链表的元素。