用c语言写一个动物识别系统要求对24个特征进行编号,推断出七种动物
时间: 2023-05-19 15:06:09 浏览: 55
非常感谢您的问题!以下是一个简单的C语言程序,可以对24个特征进行编号,并推断出七种动物:
```
#include <stdio.h>
int main() {
int features[24];
printf("请输入24个特征的值(0或1):\n");
for (int i = 0; i < 24; i++) {
scanf("%d", &features[i]);
}
int animal = -1;
if (features[0] == 1 && features[1] == 1 && features[2] == 1 && features[3] == 1 && features[4] == 1 && features[5] == 1 && features[6] == 1) {
animal = 0; // 老虎
} else if (features[0] == 1 && features[1] == 1 && features[2] == 1 && features[3] == 1 && features[4] == 1 && features[5] == 0 && features[6] == 0) {
animal = 1; // 狮子
} else if (features[0] == 0 && features[1] == 1 && features[2] == 1 && features[3] == 0 && features[4] == 1 && features[5] == 1 && features[6] == 0) {
animal = 2; // 斑马
} else if (features[0] == 0 && features[1] == 1 && features[2] == 0 && features[3] == 0 && features[4] == 1 && features[5] == 1 && features[6] == 0) {
animal = 3; // 长颈鹿
} else if (features[0] == 0 && features[1] == 0 && features[2] == 1 && features[3] == 0 && features[4] == 1 && features[5] == 1 && features[6] == 0) {
animal = 4; // 斑马
} else if (features[0] == 0 && features[1] == 0 && features[2] == 1 && features[3] == 0 && features[4] == 1 && features[5] == 0 && features[6] == 0) {
animal = 5; // 猴子
} else if (features[0] == 0 && features[1] == 0 && features[2] == 0 && features[3] == 1 && features[4] == 0 && features[5] == 1 && features[6] == 0) {
animal = 6; // 蛇
}
if (animal == -1) {
printf("无法识别该动物\n");
} else {
printf("该动物是第%d种\n", animal + 1);
}
return 0;
}
```
希望这个程序能够帮助您!如果您有任何其他问题,请随时问我。