C语言编写残缺棋盘问题代码

以下是一个解决残缺棋盘问题的C语言代码：

#include<stdio.h>
#include<math.h>

#define MAXN 1024

int tile = 1; // 全局变量，记录铺的方块数
int board[MAXN][MAXN]; // 棋盘
int special_row, special_col; // 特殊方格的行和列

// 把棋盘分成四个象限
void divide(int tr, int tc, int dr, int dc, int size) {
    if(size == 1) return; // 边界条件

    int t_mid_r = (tr + dr) / 2; // 计算上半部分棋盘中心的行
    int t_mid_c = (tc + dc) / 2; // 计算上半部分棋盘中心的列
    int d_mid_r = t_mid_r + 1; // 计算下半部分棋盘中心的行
    int d_mid_c = t_mid_c + 1; // 计算下半部分棋盘中心的列

    // 对左上象限进行递归
    if(special_row <= t_mid_r && special_col <= t_mid_c) {
        board[d_mid_r][d_mid_c] = board[t_mid_r][t_mid_c] = tile++;
        board[d_mid_r][t_mid_c+1] = board[t_mid_r+1][t_mid_c] = tile++;
        divide(tr, tc, t_mid_r, t_mid_c, size/2);
    }
    else {
        board[t_mid_r][t_mid_c] = tile++;
        board[d_mid_r][t_mid_c] = tile++;
        board[t_mid_r][d_mid_c] = tile++;
        board[d_mid_r][d_mid_c] = tile++;
        divide(tr, tc, t_mid_r, t_mid_c, size/2);
    }

    // 对右上象限进行递归
    if(special_row <= t_mid_r && special_col > t_mid_c) {
        board[d_mid_r][t_mid_c] = board[t_mid_r][d_mid_c] = tile++;
        board[d_mid_r][d_mid_c] = board[t_mid_r+1][t_mid_c+1] = tile++;
        divide(tr, t_mid_c+1, t_mid_r, dc, size/2);
    }
    else {
        board[t_mid_r][d_mid_c] = tile++;
        board[d_mid_r][d_mid_c] = tile++;
        board[t_mid_r+1][t_mid_c+1] = tile++;
        board[d_mid_r][t_mid_c] = tile++;
        divide(tr, t_mid_c+1, t_mid_r, dc, size/2);
    }

    // 对左下象限进行递归
    if(special_row > t_mid_r && special_col <= t_mid_c) {
        board[t_mid_r][d_mid_c] = board[d_mid_r][t_mid_c] = tile++;
        board[t_mid_r+1][t_mid_c+1] = board[d_mid_r][d_mid_c] = tile++;
        divide(t_mid_r+1, tc, dr, t_mid_c, size/2);
    }
    else {
        board[t_mid_r][d_mid_c] = tile++;
        board[d_mid_r][t_mid_c] = tile++;
        board[t_mid_r+1][t_mid_c+1] = tile++;
        board[d_mid_r][d_mid_c] = tile++;
        divide(t_mid_r+1, tc, dr, t_mid_c, size/2);
    }

    // 对右下象限进行递归
    if(special_row > t_mid_r && special_col > t_mid_c) {
        board[t_mid_r][d_mid_c] = board[d_mid_r][t_mid_c] = tile++;
        board[t_mid_r+1][t_mid_c] = board[d_mid_r][d_mid_c] = tile++;
        divide(t_mid_r+1, t_mid_c+1, dr, dc, size/2);
    }
    else {
        board[t_mid_r][d_mid_c] = tile++;
        board[d_mid_r][t_mid_c] = tile++;
        board[t_mid_r+1][t_mid_c] = tile++;
        board[d_mid_r][d_mid_c] = tile++;
        divide(t_mid_r+1, t_mid_c+1, dr, dc, size/2);
    }
}

int main() {
    int k, i, j;
    scanf("%d%d%d", &k, &special_row, &special_col);

    // 计算棋盘大小
    int size = pow(2, k);

    // 把特殊方格填上，从1开始填充
    board[special_row][special_col] = 0;

    // 对棋盘进行递归铺砖
    divide(0, 0, size-1, size-1, size);

    // 输出棋盘
    for(i = 0; i < size; i++) {
        for(j = 0; j < size; j++) {
            printf("%-3d", board[i][j]);
        }
        printf("\n");
    }

    return 0;
}

该代码中使用了分治算法，把棋盘分成四个象限，然后对每个象限进行递归铺砖。在铺砖的过程中，根据特殊方格所在的象限，分别对四个象限进行递归处理。最后输出棋盘即可。