生成一个求方程的根的c语言代码不要注释

#include <stdio.h>
#include <math.h>

int main() {
    double a, b, c, delta, x1, x2;
    printf("请输入方程的三个系数（a,b,c）：");
    scanf("%lf%lf%lf", &a, &b, &c);
    delta = b * b - 4 * a * c;
    if (delta > 0) {
        x1 = (-b + sqrt(delta)) / (2 * a);
        x2 = (-b - sqrt(delta)) / (2 * a);
        printf("方程的两个实根分别为：x1=%.2lf, x2=%.2lf\n", x1, x2);
    } else if (delta == 0) {
        x1 = x2 = -b / (2 * a);
        printf("方程的唯一实根为：x=%.2lf\n", x1);
    } else {
        double realPart = -b / (2 * a);
        double imagPart = sqrt(-delta) / (2 * a);
        printf("方程的两个虚根分别为：x1=%.2lf+%.2lfi, x2=%.2lf-%.2lfi\n", realPart, imagPart, realPart, imagPart);
    }
    return 0;
}

相关问题

生成一个求解一元三次方程的C语言代码

以下是求解一元三次方程的C语言代码：

#include <stdio.h>
#include <math.h>

int main()
{
double a, b, c, d;
double x1, x2, x3;
printf("请输入一元三次方程的系数a、b、c：\n");
scanf("%lf %lf %lf", &a, &b, &c);
d = b * b - 3 * a * c;
if (d < 0)
{
printf("方程无实数解。\n");
}
else if (d == 0)
{
x1 = x2 = x3 = -b / (3 * a);
printf("方程的三个实数解为：x1=x2=x3=%lf。\n", x1);
}
else
{
x1 = (-b + sqrt(d)) / (3 * a);
x2 = (-b - sqrt(d)) / (3 * a);
x3 = (2 * b + sqrt(d)) / (3 * a);
printf("方程的三个实数解为：x1=%lf，x2=%lf，x3=%lf。\n", x1, x2, x3);
}
return 0;
}

生成一个求解三阶方程的C语言代码

我可以为您提供一个求解三阶方程的C语言代码，代码如下：

#include <stdio.h>
#include <math.h>

int main()
{
    double a, b, c, d, x1, x2, x3, p, q;
    printf("请输入三阶方程的系数（a,b,c）：");
    scanf("%lf %lf %lf", &a, &b, &c);
    d = b * b - 3 * a * c;
    if (fabs(a) < 1e-6 && fabs(b) < 1e-6 && fabs(c) < 1e-6) {
        printf("方程根是任意的\n");
    } else if (fabs(a) < 1e-6 && fabs(b) < 1e-6) {
        printf("方程无解\n");
    } else if (fabs(a) < 1e-6) {
        printf("方程有一个根: %lf\n", -c / b);
    } else if (d > 1e-6) {
        p = (-b + sqrt(d)) / (3 * a);
        q = (-b - sqrt(d)) / (3 * a);
        x1 = -b / (3 * a) + p + q;
        x2 = (-b + 2 * p * (1 + I * sqrt(3))) / (3 * a);
        x3 = (-b + 2 * q * (1 - I * sqrt(3))) / (3 * a);
        printf("方程有三个复数根：\n");
        printf("x1 = %lf\n", x1);
        printf("x2 = %lf + %lf i\n", creal(x2), cimag(x2));
        printf("x3 = %lf + %lf i\n", creal(x3), cimag(x3));
    } else if (fabs(d) < 1e-6) {
        x1 = -b / (3 * a) + 2 * c / (3 * a) * pow(d, -0.5);
        x2 = -c / (3 * a) - pow(d, -0.5) / 3;
        x3 = -c / (3 * a) + pow(d, -0.5) / 3;
        printf("方程有三个实数根：\n");
        printf("x1 = %lf\n", x1);
        printf("x2 = %lf\n", x2);
        printf("x3 = %lf\n", x3);
    } else if (d < -1e-6) {
        double t = acos(sqrt(-27 * a * a / d) / 2) / 3;
        x1 = -b / (3 * a);
        x2 = 2 * sqrt(-d / 3) * cos(t) - b / (3 * a);
        x3 = 2 * sqrt(-d / 3) * cos(t + 2 * M_PI / 3) - b / (3 * a);
        printf("方程有三个实数根：\n");
        printf("x1 = %lf\n", x1);
        printf("x2 = %lf\n", x2);
        printf("x3 = %lf\n", x3);
    }
    return 0;
}

这个 C 语言代码可以求解三阶方程的根，通过输入方程的系数 a、b、c，可以输出方程的根。如果系数为零或方程无解，程序会输出相应的提示信息。当然，如果您有其他更具体的要求，我也可以进行修改和定制。