用c语言写一个井字棋小游戏

好的，以下是一个简单的井字棋小游戏的 C 语言代码：

#include <stdio.h>

char board[3][3] = { {' ', ' ', ' '}, {' ', ' ', ' '}, {' ', ' ', ' '} };

void print_board()
{
    printf("\n");
    printf(" %c | %c | %c\n", board[0][0], board[0][1], board[0][2]);
    printf("-----------\n");
    printf(" %c | %c | %c\n", board[1][0], board[1][1], board[1][2]);
    printf("-----------\n");
    printf(" %c | %c | %c\n", board[2][0], board[2][1], board[2][2]);
    printf("\n");
}

int check_win()
{
    int i;
    for (i = 0; i < 3; i++) {
        if ((board[i][0] == board[i][1] && board[i][1] == board[i][2] && board[i][0] != ' ') ||
            (board[0][i] == board[1][i] && board[1][i] == board[2][i] && board[0][i] != ' ')) {
            return 1;
        }
    }
    if ((board[0][0] == board[1][1] && board[1][1] == board[2][2] && board[0][0] != ' ') ||
        (board[0][2] == board[1][1] && board[1][1] == board[2][0] && board[0][2] != ' ')) {
        return 1;
    }
    return 0;
}

int main()
{
    int i, j, turn = 0;
    printf("Welcome to Tic Tac Toe in C!\n");
    printf("Player 1 (X) - Player 2 (O)\n");
    for (i = 0; i < 9; i++) {
        print_board();
        printf("Player %d's turn.\n", turn % 2 + 1);
        printf("Enter row (0-2): ");
        scanf("%d", &j);
        printf("Enter column (0-2): ");
        scanf("%d", &i);
        if (board[i][j] != ' ') {
            printf("That cell is already taken.\n");
            turn--;
        } else {
            board[i][j] = turn % 2 ? 'O' : 'X';
        }
        if (check_win()) {
            printf("Player %d wins!\n", turn % 2 + 1);
            print_board();
            return 0;
        }
        turn++;
    }
    printf("It's a tie!\n");
    print_board();
    return 0;
}

这个代码实现了一个简单的井字棋小游戏，首先打印出初始的空棋盘，然后轮流让两个玩家下棋。每次下棋时，程序会提示用户输入想要落子的行和列，如果该位置已经有棋子则会提示用户重新输入。在每次下棋之后，程序会检查是否有任何一方获胜，如果有则输出该玩家获胜的信息并结束游戏，否则游戏继续，直到棋盘填满为止，此时宣布平局并结束游戏。

希望这个代码可以对你有所帮助！