请用while编程 问题: 读入整数k 求和S=1+2+4+8+16+……n 期中n是满足规律的且不大于k的最大整数。输出总和s 输入样例: 10 输出样例: 15 数据规模 1<= k <=1000000
时间: 2024-01-01 10:04:14 浏览: 46
好的,我来为您编写代码:
```python
k = int(input())
n = 1
s = 0
while n <= k:
s += n
n *= 2
print(s)
```
解释一下,我们首先读入整数k,然后初始化n为1,s为0。然后在while循环中,每次将n加到s中,然后将n乘以2,直到n大于k为止。最后输出s即可。
相关问题
典型循环:s=1!+2!+3!+……+n!,用三种循环编程
1. for循环
```
n = int(input("请输入一个正整数:"))
s = 0
for i in range(1, n+1):
fac = 1
for j in range(1, i+1):
fac *= j
s += fac
print("s =", s)
```
2. while循环
```
n = int(input("请输入一个正整数:"))
s = 0
i = 1
while i <= n:
fac = 1
j = 1
while j <= i:
fac *= j
j += 1
s += fac
i += 1
print("s =", s)
```
3. do-while循环
```
n = int(input("请输入一个正整数:"))
s = 0
i = 1
while True:
fac = 1
j = 1
while j <= i:
fac *= j
j += 1
s += fac
i += 1
if i > n:
break
print("s =", s)
```
c++ 典型循环:s=1!+2!+3!+……+n!,用三种循环编程
1. 使用for循环
```c
#include <stdio.h>
int main() {
int n, s = 1;
printf("请输入n:");
scanf("%d", &n);
for(int i=1; i<=n; i++) {
int fact = 1;
for(int j=1; j<=i; j++) {
fact *= j;
}
s *= fact;
}
printf("s = %d\n", s);
return 0;
}
```
2. 使用while循环
```c
#include <stdio.h>
int main() {
int n, i = 1, s = 1;
printf("请输入n:");
scanf("%d", &n);
while(i <= n) {
int j = 1, fact = 1;
while(j <= i) {
fact *= j;
j++;
}
s *= fact;
i++;
}
printf("s = %d\n", s);
return 0;
}
```
3. 使用do-while循环
```c
#include <stdio.h>
int main() {
int n, i = 1, s = 1;
printf("请输入n:");
scanf("%d", &n);
do {
int j = 1, fact = 1;
do {
fact *= j;
j++;
} while(j <= i);
s *= fact;
i++;
} while(i <= n);
printf("s = %d\n", s);
return 0;
}
```