嵌入式实验,cortex-a9电阻器若阻值大于10则灯亮蜂鸣器响,不然则灯灭蜂鸣器停
时间: 2024-01-17 12:02:44 浏览: 25
这个问题需要您编写嵌入式程序来实现。以下是一个可能的程序代码示例,可以实现您所描述的功能:
```c
#include <stdio.h>
#include "platform.h"
#include "xil_printf.h"
#include "xparameters.h"
#include "xgpio.h"
#define GPIO_DEVICE_ID XPAR_AXI_GPIO_0_DEVICE_ID
#define LED_CHANNEL 1
#define BUZZER_CHANNEL 2
#define RESISTOR_CHANNEL 1
XGpio gpio;
int main()
{
init_platform();
int status = XGpio_Initialize(&gpio, GPIO_DEVICE_ID);
if (status != XST_SUCCESS) {
xil_printf("Error initializing GPIO.\n");
return XST_FAILURE;
}
XGpio_SetDataDirection(&gpio, LED_CHANNEL, 0x0); // set LED channel as output
XGpio_SetDataDirection(&gpio, BUZZER_CHANNEL, 0x0); // set Buzzer channel as output
XGpio_SetDataDirection(&gpio, RESISTOR_CHANNEL, 0x1); // set Resistor channel as input
while (1) {
u32 resistor_value = XGpio_DiscreteRead(&gpio, RESISTOR_CHANNEL);
if (resistor_value > 10) {
XGpio_DiscreteWrite(&gpio, LED_CHANNEL, 0x1); // turn on LED
XGpio_DiscreteWrite(&gpio, BUZZER_CHANNEL, 0x1); // turn on buzzer
} else {
XGpio_DiscreteWrite(&gpio, LED_CHANNEL, 0x0); // turn off LED
XGpio_DiscreteWrite(&gpio, BUZZER_CHANNEL, 0x0); // turn off buzzer
}
}
cleanup_platform();
return 0;
}
```
这个程序可以通过 AXI GPIO 控制 LED 和蜂鸣器的开关状态,并且读取电阻器的输入值。如果电阻器的值大于 10,则 LED 亮起并且蜂鸣器响,否则 LED 熄灭并且蜂鸣器停止。注意,这个代码示例仅供参考,请根据实际情况进行修改和调试。