c语言编写一个函数，将数字0-6分别转换为"Sunday","Monday","Tuesday","Wednsday","Thursday","Friday","Saturday"。char * int2week(int week)

下面是一个示例函数，可以将数字转换为对应的星期几名称：

char* int2week(int week) {
    static char* weeks[] = {"Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"};
    if (week >= 0 && week <= 6) {
        return weeks[week];
    } else {
        return NULL;
    }
}

该函数接受一个整数参数 `week`，并返回对应的星期几名称。如果 `week` 不在 0-6 的范围内，则返回 `NULL`。

使用示例：

#include <stdio.h>

int main() {
    int week = 3;
    char* weekday = int2week(week);
    if (weekday != NULL) {
        printf("The day is %s\n", weekday);
    } else {
        printf("Invalid input\n");
    }
    return 0;
}

输出结果：

The day is Wednesday

相关问题

5、编写一个函数,将数字0-6分别转换为Sunday,Monday,Tuesday,Wednsday,Thursday,Friday,Saturday。char * int

下面是一个示例函数，可以将数字转换为对应的星期几名称：

char* int_to_weekday(int num) {
    char* weekdays[] = {"Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"};

    if (num >= 0 && num <= 6) {
        return weekdays[num];
    } else {
        return "Invalid input";
    }
}

该函数接受一个整数参数 `num`，并返回对应的星期几名称。如果 `num` 不在 0-6 的范围内，则返回字符串 "Invalid input"。

使用示例：

#include <stdio.h>

int main() {
    int num = 3;
    char* weekday = int_to_weekday(num);
    printf("The day is %s\n", weekday);
    return 0;
}

输出结果：

The day is Wednesday

编写一个函数，将数字0-6分别转换为"Sunday","Monday","Tuesday","Wednsday","Thursday","Friday","Saturday"。char * int2week(int week)

好的，以下是函数的代码实现：

char* int2week(int week) {
    char* weekStr[] = {"Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"};
    if (week >= 0 && week <= 6) {
        return weekStr[week];
    } else {
        return NULL;
    }
}

这个函数接受一个数字参数 `week`，如果在 0 到 6 的范围内，就返回对应的星期字符串；否则返回 NULL。