对二维数组a[M][M]的处理: (1)实现数组a[M][M]的输入和输出; (2)找出数组a[M][M]的最大值或最小值; (3)对数组a[M][M]行列互换; (4)求数组a[M][M]所有元素的和及平均值; (5) 求a[M][M]对角线元素之和、下三角元素之和、上三角元素之和。 并输出运行结果
时间: 2023-10-01 12:07:38 浏览: 29
好的,我明白了。以下是对您的问题的回答:
(1)实现数组a[M][M]的输入和输出:
```cpp
#include <iostream>
using namespace std;
const int M = 3; // 假设M为3
void inputArray(int a[M][M]) {
cout << "请输入数组元素:" << endl;
for (int i = 0; i < M; i++) {
for (int j = 0; j < M; j++) {
cin >> a[i][j];
}
}
}
void outputArray(int a[M][M]) {
cout << "数组元素为:" << endl;
for (int i = 0; i < M; i++) {
for (int j = 0; j < M; j++) {
cout << a[i][j] << " ";
}
cout << endl;
}
}
```
(2)找出数组a[M][M]的最大值或最小值:
```cpp
int findMaxValue(int a[M][M]) {
int maxValue = a[0][0];
for (int i = 0; i < M; i++) {
for (int j = 0; j < M; j++) {
if (a[i][j] > maxValue) {
maxValue = a[i][j];
}
}
}
return maxValue;
}
int findMinValue(int a[M][M]) {
int minValue = a[0][0];
for (int i = 0; i < M; i++) {
for (int j = 0; j < M; j++) {
if (a[i][j] < minValue) {
minValue = a[i][j];
}
}
}
return minValue;
}
```
(3)对数组a[M][M]行列互换:
```cpp
void transposeArray(int a[M][M]) {
for (int i = 0; i < M; i++) {
for (int j = i + 1; j < M; j++) {
int temp = a[i][j];
a[i][j] = a[j][i];
a[j][i] = temp;
}
}
}
```
(4)求数组a[M][M]所有元素的和及平均值:
```cpp
void calculateSumAndAverage(int a[M][M], int& sum, float& average) {
sum = 0;
for (int i = 0; i < M; i++) {
for (int j = 0; j < M; j++) {
sum += a[i][j];
}
}
average = static_cast<float>(sum) / (M * M);
}
```
(5)求a[M][M]对角线元素之和、下三角元素之和、上三角元素之和:
```cpp
int calculateDiagonalSum(int a[M][M]) {
int sum = 0;
for (int i = 0; i < M; i++) {
sum += a[i][i];
}
return sum;
}
int calculateLowerTriangleSum(int a[M][M]) {
int sum = 0;
for (int i = 0; i < M; i++) {
for (int j = 0; j <= i; j++) {
sum += a[i][j];
}
}
return sum;
}
int calculateUpperTriangleSum(int a[M][M]) {
int sum = 0;
for (int i = 0; i < M; i++) {
for (int j = i; j < M; j++) {
sum += a[i][j];
}
}
return sum;
}
```
您可以在主函数中调用这些函数来实现相应的功能。希望这些代码能帮助到您!
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