hive像表中插入年月日 时分秒的数据
时间: 2023-08-07 14:05:38 浏览: 166
Hive小表的测试数据
可以使用Hive的内置函数`from_unixtime()`将Unix时间戳转换为日期时间格式,然后将其插入到表中。假设你要插入的数据是当前时间,可以按以下方式操作:
1. 创建表,表字段包括时间戳(ts)、年(year)、月(month)、日(day)、小时(hour)、分钟(minute)和秒(second):
```
CREATE TABLE my_table (
ts BIGINT,
year INT,
month INT,
day INT,
hour INT,
minute INT,
second INT
);
```
2. 使用`from_unixtime()`函数获取当前时间戳和对应的年月日时分秒:
```
SELECT
unix_timestamp() AS ts,
from_unixtime(unix_timestamp(), 'yyyy') AS year,
from_unixtime(unix_timestamp(), 'MM') AS month,
from_unixtime(unix_timestamp(), 'dd') AS day,
from_unixtime(unix_timestamp(), 'HH') AS hour,
from_unixtime(unix_timestamp(), 'mm') AS minute,
from_unixtime(unix_timestamp(), 'ss') AS second;
```
3. 将获取到的年月日时分秒插入到表中:
```
INSERT INTO my_table
SELECT
unix_timestamp() AS ts,
from_unixtime(unix_timestamp(), 'yyyy') AS year,
from_unixtime(unix_timestamp(), 'MM') AS month,
from_unixtime(unix_timestamp(), 'dd') AS day,
from_unixtime(unix_timestamp(), 'HH') AS hour,
from_unixtime(unix_timestamp(), 'mm') AS minute,
from_unixtime(unix_timestamp(), 'ss') AS second;
```
这样就可以将带有年月日时分秒的数据插入到Hive表中了。
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