带小数点的十进制转换八进制C语言代码

以下是将带小数点的十进制数转换为八进制数的C语言代码：

#include <stdio.h>

int main() {
    double decimal;
    int integer, quotient, remainder;
    int octal_int = 0, octal_frac = 0;
    int i = 1, j = 1;
    printf("Enter a decimal number: ");
    scanf("%lf", &decimal);
    integer = (int) decimal;
    decimal = decimal - integer;

    // Convert integer part to octal
    quotient = integer;
    while (quotient != 0) {
        remainder = quotient % 8;
        octal_int = octal_int + remainder * i;
        i = i * 10;
        quotient = quotient / 8;
    }

    // Convert fractional part to octal
    while (decimal > 0) {
        decimal = decimal * 8;
        integer = (int) decimal;
        octal_frac = octal_frac + integer * j;
        j = j * 10;
        decimal = decimal - integer;
    }

    // Print octal number
    printf("Octal equivalent: %d.%d", octal_int, octal_frac);

    return 0;
}

该程序首先从用户输入的十进制数中提取整数部分和小数部分，并将整数部分转换为八进制数。然后，它将小数部分乘以8并将结果转换为整数，重复此过程直到小数部分为零。最后，程序将整数部分和小数部分组合成一个八进制数并输出结果。