用python写一个ai井字棋游戏的代码

好的，以下是一个简单的 Python AI 井字棋游戏代码：

import random

def draw_board(board):
    # This function prints out the board that it was passed.

    # "board" is a list of 10 strings representing the board (ignore index 0)
    print('   |   |')
    print(' ' + board[7] + ' | ' + board[8] + ' | ' + board[9])
    print('   |   |')
    print('-----------')
    print('   |   |')
    print(' ' + board[4] + ' | ' + board[5] + ' | ' + board[6])
    print('   |   |')
    print('-----------')
    print('   |   |')
    print(' ' + board[1] + ' | ' + board[2] + ' | ' + board[3])
    print('   |   |')

def input_player_letter():
    # Lets the player type which letter they want to be.
    # Returns a list with the player's letter as the first item, and the computer's letter as the second.
    letter = ''
    while not (letter == 'X' or letter == 'O'):
        print('Do you want to be X or O?')
        letter = input().upper()

    # the first element in the tuple is the player's letter, the second is the computer's letter.
    if letter == 'X':
        return ['X', 'O']
    else:
        return ['O', 'X']

def who_goes_first():
    # Randomly choose the player who goes first.
    if random.randint(0, 1) == 0:
        return 'computer'
    else:
        return 'player'

def make_move(board, letter, move):
    board[move] = letter

def is_winner(bo, le):
    # Given a board and a player's letter, this function returns True if that player has won.
    # We use bo instead of board and le instead of letter so we don't have to type as much.
    return ((bo[7] == le and bo[8] == le and bo[9] == le) or # across the top
    (bo[4] == le and bo[5] == le and bo[6] == le) or # across the middle
    (bo[1] == le and bo[2] == le and bo[3] == le) or # across the bottom
    (bo[7] == le and bo[4] == le and bo[1] == le) or # down the left side
    (bo[8] == le and bo[5] == le and bo[2] == le) or # down the middle
    (bo[9] == le and bo[6] == le and bo[3] == le) or # down the right side
    (bo[7] == le and bo[5] == le and bo[3] == le) or # diagonal
    (bo[9] == le and bo[5] == le and bo[1] == le)) # diagonal

def get_board_copy(board):
    # Make a duplicate of the board list and return it the duplicate.
    dupe_board = []

    for i in board:
        dupe_board.append(i)

    return dupe_board

def is_space_free(board, move):
    # Return true if the passed move is free on the passed board.
    return board[move] == ' '

def get_player_move(board):
    # Let the player type in their move.
    move = ' '
    while move not in '1 2 3 4 5 6 7 8 9'.split() or not is_space_free(board, int(move)):
        print('What is your next move? (1-9)')
        move = input()
    return int(move)

def choose_random_move_from_list(board, movesList):
    # Returns a valid move from the passed list on the passed board.
    # Returns None if there is no valid move.
    possibleMoves = []
    for i in movesList:
        if is_space_free(board, i):
            possibleMoves.append(i)

    if len(possibleMoves) != 0:
        return random.choice(possibleMoves)
    else:
        return None

def get_computer_move(board, computerLetter):
    # Given a board and the computer's letter, determine where to move and return that move.
    if computerLetter == 'X':
        playerLetter = 'O'
    else:
        playerLetter = 'X'

    # Here is our algorithm for our Tic Tac Toe AI:
    # First, check if we can win in the next move
    for i in range(1, 10):
        copy = get_board_copy(board)
        if is_space_free(copy, i):
            make_move(copy, computerLetter, i)
            if is_winner(copy, computerLetter):
                return i

    # Check if the player could win on their next move, and block them.
    for i in range(1, 10):
        copy = get_board_copy(board)
        if is_space_free(copy, i):
            make_move(copy, playerLetter, i)
            if is_winner(copy, playerLetter):
                return i

    # Try to take one of the corners, if they are free.
    move = choose_random_move_from_list(board, [1, 3, 7, 9])
    if move != None:
        return move

    # Try to take the center, if it is free.
    if is_space_free(board, 5):
        return 5

    # Move on one of the sides.
    return choose_random_move_from_list(board, [2, 4, 6, 8])

def is_board_full(board):
    # Return True if every space on the board has been taken. Otherwise return False.
    for i in range(1, 10):
        if is_space_free(board, i):
            return False
    return True

print('Welcome to Tic Tac Toe!')

while True:
    # Reset the board
    theBoard = [' '] * 10
    playerLetter, computerLetter = input_player_letter()
    turn = who_goes_first()
    print('The ' + turn + ' will go first.')
    gameIsPlaying = True

    while gameIsPlaying:
        if turn == 'player':
            # Player's turn.
            draw_board(theBoard)
            move = get_player_move(theBoard)
            make_move(theBoard, playerLetter, move)

            if is_winner(theBoard, playerLetter):
                draw_board(theBoard)
                print('Hooray! You have won the game!')
                gameIsPlaying = False
            else:
                if is_board_full(theBoard):
                    draw_board(theBoard)
                    print('The game is a tie!')
                    break
                else:
                    turn = 'computer'

        else:
            # Computer's turn.
            move = get_computer_move(theBoard, computerLetter)
            make_move(theBoard, computerLetter, move)

            if is_winner(theBoard, computerLetter):
                draw_board(theBoard)
                print('The computer has beaten you! You lose.')
                gameIsPlaying = False
            else:
                if is_board_full(theBoard):
                    draw_board(theBoard)
                    print('The game is a tie!')
                    break
                else:
                    turn = 'player'

    print('Do you want to play again? (yes or no)')
    if not input().lower().startswith('y'):
        break

希望这个代码能够帮到你！