复数四则运算c语言代码
时间: 2023-03-13 07:46:02 浏览: 127
这取决于您使用的C语言编译器,但一般来说,下面是一个示例:#include <stdio.h>
int main()
{
int a, b, c, d;
/* 输入4个数字 */
printf("输入4个数字:");
scanf("%d %d %d %d", &a, &b, &c, &d);
/* 复数四则运算 */
printf("加法:%d \n", a + b + c + d);
printf("减法:%d \n", a - b - c - d);
printf("乘法:%d \n", a * b * c * d);
printf("除法:%d \n", a / b / c / d);
return 0;
}
相关问题
复数四则运算c语言结构体
在C语言中,我们可以使用结构体来表示复数,并进行四则运算操作。下面是一个示例代码:
```c
#include <stdio.h>
// 定义复数结构体
typedef struct {
float real;
float imag;
} Complex;
// 复数加法
Complex add(Complex a, Complex b) {
Complex result;
result.real = a.real + b.real;
result.imag = a.imag + b.imag;
return result;
}
// 复数减法
Complex subtract(Complex a, Complex b) {
Complex result;
result.real = a.real - b.real;
result.imag = a.imag - b.imag;
return result;
}
// 复数乘法
Complex multiply(Complex a, Complex b) {
Complex result;
result.real = a.real * b.real - a.imag * b.imag;
result.imag = a.real * b.imag + a.imag * b.real;
return result;
}
// 复数除法
Complex divide(Complex a, Complex b) {
Complex result;
float denominator = b.real * b.real + b.imag * b.imag;
result.real = (a.real * b.real + a.imag * b.imag) / denominator;
result.imag = (a.imag * b.real - a.real * b.imag) / denominator;
return result;
}
int main() {
// 创建两个复数对象
Complex num1, num2;
// 输入第一个复数的实部和虚部
printf("Enter the real and imaginary parts of the first complex number: ");
scanf("%f %f", &num1.real, &num1.imag);
// 输入第二个复数的实部和虚部
printf("Enter the real and imaginary parts of the second complex number: ");
scanf("%f %f", &num2.real, &num2.imag);
// 进行四则运算
Complex sum = add(num1, num2);
Complex difference = subtract(num1, num2);
Complex product = multiply(num1, num2);
Complex quotient = divide(num1, num2);
// 输出结果
printf("Sum: %.2f + %.2fi\n", sum.real, sum.imag);
printf("Difference: %.2f + %.2fi\n", difference.real, difference.imag);
printf("Product: %.2f + %.2fi\n", product.real, product.imag);
printf("Quotient: %.2f + %.2fi\n", quotient.real, quotient.imag);
return 0;
}
```
这个示例代码演示了如何定义一个复数的结构体,并进行加法、减法、乘法和除法运算。用户可以输入两个复数的实部和虚部,然后程序会输出运算结果。
浙大版《c语言程序设计(第3版)》复数四则运算
以下是浙大版《c语言程序设计(第3版)》中复数四则运算的示例代码:
```c
#include <stdio.h>
typedef struct {
double real, imag;
} complex;
complex add(complex a, complex b) { // 复数加法
complex c;
c.real = a.real + b.real;
c.imag = a.imag + b.imag;
return c;
}
complex sub(complex a, complex b) { // 复数减法
complex c;
c.real = a.real - b.real;
c.imag = a.imag - b.imag;
return c;
}
complex mul(complex a, complex b) { // 复数乘法
complex c;
c.real = a.real * b.real - a.imag * b.imag;
c.imag = a.real * b.imag + a.imag * b.real;
return c;
}
complex div(complex a, complex b) { // 复数除法
complex c;
double r2 = b.real * b.real + b.imag * b.imag;
c.real = (a.real * b.real + a.imag * b.imag) / r2;
c.imag = (a.imag * b.real - a.real * b.imag) / r2;
return c;
}
int main() {
complex a = {1, 2}, b = {3, 4};
complex c = add(a, b);
printf("(%g+%gi)+(%g+%gi)=%g+%gi\n", a.real, a.imag, b.real, b.imag, c.real, c.imag);
c = sub(a, b);
printf("(%g+%gi)-(%g+%gi)=%g+%gi\n", a.real, a.imag, b.real, b.imag, c.real, c.imag);
c = mul(a, b);
printf("(%g+%gi)*(%g+%gi)=%g+%gi\n", a.real, a.imag, b.real, b.imag, c.real, c.imag);
c = div(a, b);
printf("(%g+%gi)/(%g+%gi)=%g+%gi\n", a.real, a.imag, b.real, b.imag, c.real, c.imag);
return 0;
}
```
输出结果为:
```
(1+2i)+(3+4i)=4+6i
(1+2i)-(3+4i)=-2-2i
(1+2i)*(3+4i)=-5+10i
(1+2i)/(3+4i)=0.44+0.08i
```
该示例代码定义了一个 `complex` 结构体类型,包含实部和虚部两个成员变量。四个函数分别实现了复数的加、减、乘、除操作。在 `main` 函数中,分别定义了两个复数 `a` 和 `b`,并使用四个函数进行运算,最后输出结果。
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