中望cad中求两条直线的中垂线交点的c++代码

以下是中望CAD中求两条直线的中垂线交点的 C++ 代码：

AcGePoint3d GetPerpendicularBisectorIntersection(const AcGePoint3d& p1, const AcGePoint3d& p2, const AcGePoint3d& p3, const AcGePoint3d& p4)
{
    AcGePoint3d ptMid1 = (p1 + p2) / 2.0;
    AcGePoint3d ptMid2 = (p3 + p4) / 2.0;

    AcGeVector3d vec1 = p2 - p1;
    AcGeVector3d vec2 = p4 - p3;

    vec1.rotateBy(kPi / 2.0, AcGeVector3d::kZAxis);
    vec2.rotateBy(kPi / 2.0, AcGeVector3d::kZAxis);

    AcGeLine3d line1(ptMid1, vec1);
    AcGeLine3d line2(ptMid2, vec2);

    AcGePoint3d ptInt;
    line1.intersectWith(line2, AcGe::kOnBothOperands, ptInt);

    return ptInt;
}

其中，`p1` 和 `p2` 是第一条直线的两个端点，`p3` 和 `p4` 是第二条直线的两个端点。函数返回两条直线的中垂线的交点。