clear all; clc; du = pi/180; a = [0+0.001, 185+0.0079, 0+0.005, 120+0.12]; alpha = [pi/2+0.003, 0+0.001, pi/2+0.005, pi/2]; d = [0+0.001, 0+0.0079, 90+0.005, 0+0.12]; theta = [90du+0.02, 0, 0.023, 0.08]; beta = zeros(1, 4)+0; L1(1) = Link('d', d(1), 'a', a(1), 'alpha', alpha(1), 'qlim', [180du, 365du], 'modified'); L1(2) = Link('d', d(2), 'a', a(2), 'alpha', alpha(2), 'qlim', [3du, 63du], 'modified'); L1(3) = Link('d', d(3), 'a', a(3), 'alpha', alpha(3), 'qlim', [60du, 120du], 'modified'); L1(4) = Link('d', d(4), 'a', a(4), 'alpha', alpha(4), 'qlim', [230du, 326du], 'modified'); Needle = SerialLink(L1, 'name', 'Needle'); T1 = DH(1, a(1), alpha(1), d(1), theta(1)+beta(1)); T2 = DH(2, a(2), alpha(2), d(2), theta(2)+beta(2)); T3 = DH(3, a(3), alpha(3), d(3), theta(3)+beta(3)); T4 = DH(4, a(4), alpha(4), d(4), theta(4)+beta(4)); T = T1T2T3T4; delta_a = 0.001; delta_T = zeros(4, 4); for i = 1:4 delta_T = delta_T + diff(T, a(i))*delta_a; end delta_alpha = 0.003; for i = 1:4 delta_T = delta_T + diff(T, alpha(i))*delta_alpha; end delta_d = 0.005; for i = 1:4 delta_T = delta_T + diff(T, d(i))delta_d; end delta_theta = 0.02du; for i = 1:4 delta_T = delta_T + diff(T, theta(i))*delta_theta; end delta_beta = 0.0; for i = 1:4 delta_T = delta_T + diff(T, beta(i))*delta_beta; end q = [theta(1), 0, theta(3), theta(4)]; T = Needle.fkine(q); pos = T(1:3, 4); euler = tr2eul(T, 'ZYX')/du; delta_pos = delta_T(1:3, 4); delta_euler = tr2eul(delta_T, 'ZYX')/du;上段代码显示错误使用 diff 差分阶数 N 必须为正整数标量。 出错 ceshi2 (line 28) delta_T = delta_T + diff(T, a(i))*delta_a;
时间: 2023-09-10 11:11:35 浏览: 94
根据您提供的代码,我发现在第28行出现了一个错误。错误信息显示差分阶数必须是正整数标量,而您的第二个参数a(i)是一个向量,导致了这个错误。
要解决这个问题,您需要将第28行到32行的for循环中的第二个参数改为一个正整数标量。因为diff函数的第二个参数表示差分阶数,所以您需要将它改为1,表示一阶差分。
下面是更改后的代码:
```
delta_a = 0.001;
delta_T = zeros(4, 4);
for i = 1:4
delta_T = delta_T + diff(T, 1, a(i))*delta_a;
end
delta_alpha = 0.003;
for i = 1:4
delta_T = delta_T + diff(T, 1, alpha(i))*delta_alpha;
end
delta_d = 0.005;
for i = 1:4
delta_T = delta_T + diff(T, 1, d(i))*delta_d;
end
delta_theta = 0.02*du;
for i = 1:4
delta_T = delta_T + diff(T, 1, theta(i))*delta_theta;
end
delta_beta = 0.0;
for i = 1:4
delta_T = delta_T + diff(T, 1, beta(i))*delta_beta;
end
```
请注意,我将diff函数的第二个参数更改为1,表示执行一阶差分。如果您需要进行更高阶的差分,可以将第二个参数更改为所需的正整数值。
希望这可以帮助您解决问题!
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