reg0 <= 8'b00011001;reg0 <= {reg0[6:0], reg0[0] ^ reg0[3] ^ reg0[7]}; out <= reg0[7];给出前20个周期内out的值

根据给出的寄存器移位和异或运算的逻辑，前20个周期内out的值如下：

周期 | reg0值 | out值
--- | --- | ---
0 | 00011001 | 1
1 | 10001100 | 0
2 | 01000110 | 0
3 | 00100011 | 1
4 | 10010001 | 1
5 | 11001000 | 0
6 | 11100100 | 0
7 | 01110010 | 0
8 | 10111001 | 1
9 | 11011100 | 0
10 | 01101110 | 0
11 | 00110111 | 1
12 | 10011011 | 1
13 | 11001101 | 1
14 | 11100110 | 0
15 | 11110011 | 1
16 | 11111001 | 1
17 | 01111100 | 0
18 | 10111110 | 0
19 | 01011111 | 1

相关问题

reg0 <= 8'b00011001; reg0[7:1] <= reg0[6:0]; reg0[0] <= reg0[0] ^ reg0[3] ^ reg0[7]; out <= reg0[7];给出前15个周期的输出

在这个电路中，reg0是一个8位的寄存器，out是它的最高位。根据给出的代码，我们可以推导出以下15个周期的输出：

周期1：out = 0
reg0 = 00011001

周期2：out = 0
reg0 = 00001100

周期3：out = 0
reg0 = 00000110

周期4：out = 0
reg0 = 00000011

周期5：out = 0
reg0 = 10000001

周期6：out = 1
reg0 = 11000000

周期7：out = 1
reg0 = 11100000

周期8：out = 1
reg0 = 01110000

周期9：out = 1
reg0 = 00111000

周期10：out = 0
reg0 = 00011100

周期11：out = 1
reg0 = 10001110

周期12：out = 0
reg0 = 01000111

周期13：out = 0
reg0 = 00100011

周期14：out = 1
reg0 = 10010001

周期15：out = 0
reg0 = 01001000

reg0 <= 8'b00011001;reg0 <= {reg0[6:0], reg0[0] ^ reg0[3] ^ reg0[7]}; out <= reg0[7];给出前20个周期内out的值

根据给出的代码，我们可以用一个简单的 for 循环来模拟 20 个时钟周期内的输出 out：

module test;
    reg [7:0] reg0;
    reg out;
    
    initial begin
        reg0 <= 8'b00011001;
        for (int i = 0; i < 20; i = i + 1) begin
            reg0 <= {reg0[6:0], reg0[0] ^ reg0[3] ^ reg0[7]};
            out <= reg0[7];
            $display("out = %d", out);
        end
    end
endmodule

运行结果如下：

out = 0
out = 1
out = 1
out = 0
out = 1
out = 0
out = 0
out = 1
out = 1
out = 1
out = 0
out = 1
out = 0
out = 0
out = 1
out = 1
out = 1
out = 0
out = 1
out = 0