编程计算前30项的和：s=1+(1+2)+(1+2+3)+(1+2+3+4)+…+(1+2+3+4+…+n)，用函数调用的方法python

以下是Python代码，可以计算前30项的和：

def sum_n(n):
sum = 0
for i in range(1, n+1):
sublist = [j for j in range(1, i+1)]
product = 1
for num in sublist:
product *= num
sum += product
return sum

print(sum_n(30)) # 输出答案