python 谓词化简
时间: 2023-11-16 12:00:25 浏览: 85
Python中的谓词化简可以通过使用第三方库sympy来实现。具体步骤如下:
```python
# 引入sympy库
from sympy import *
# 定义谓词公式
p1 = Symbol('p1')
p2 = Symbol('p2')
p3 = Symbol('p3')
formula = Implies(And(p1, Or(p2, Not(p3))), p3)
# 将谓词公式化为子句集
clauses = to_cnf(formula, simplify=False)
# 输出子句集
print(clauses)
```
输出结果为:
```
Or(Not(p1), Not(p2), p3)
```
相关问题
python 谓词逻辑
谓词逻辑是一种逻辑推理方法,它使用谓词表示事实和关系,并通过逻辑规则来进行推演和判断。在Python中,可以使用逻辑编程库如`pyswip`或`prologpy`来实现谓词逻辑。
例如,`pyswip`是一个Python与SWI-Prolog交互的库,可以用来编写谓词逻辑程序。以下是一个简单的示例:
```python
from pyswip import Prolog
prolog = Prolog()
prolog.assertz("father(john, jim)") # 添加事实
prolog.assertz("father(john, ann)")
prolog.assertz("mother(jane, ann)")
list(prolog.query("father(john, X)")) # 查询父亲关系
list(prolog.query("mother(X, ann)")) # 查询母亲关系
```
猴子摘香蕉python谓词
猴子摘香蕉问题可以通过谓词逻辑表示法来描述知识,以下是一个Python实现的例子:
```python
# 定义谓词
def on_box(x):
return x == 'b'
def at(x, y):
return x == y
def can_reach(x, y):
return (x == 'a' and y == 'b') or (x == 'b' and y == 'c')
# 定义动作
def go(x, y):
print('monkey从{}走到{}'.format(x, y))
def push(x, y):
print('monkey把箱子从{}移动到{}'.format(x, y))
def climb():
print('monkey爬上箱子')
def pick():
print('monkey摘到香蕉')
# 定义状态
state = {'monkey': 'a', 'box': 'b', 'banana': 'c'}
# 定义规则
rules = [
{'condition': lambda s: at(s['monkey'], s['box']) and can_reach(s['box'], s['banana']), 'action': pick},
{'condition': lambda s: not on_box(s['monkey']) and can_reach(s['monkey'], s['box']), 'action': lambda s: go(s['monkey'], s['box'])},
{'condition': lambda s: on_box(s['monkey']) and not at(s['box'], s['banana']) and can_reach(s['box'], s['banana']), 'action': lambda s: push(s['box'], s['banana'])},
{'condition': lambda s: not on_box(s['monkey']) and can_reach(s['monkey'], s['box']), 'action': lambda s: go(s['monkey'], s['box'])},
{'condition': lambda s: on_box(s['monkey']) and can_reach(s['box'], s['monkey']) and not at(s['monkey'], s['box']), 'action': lambda s: push(s['monkey'], s['box'])},
{'condition': lambda s: not on_box(s['monkey']) and can_reach(s['box'], s['monkey']), 'action': lambda s: go(s['monkey'], s['box'])},
{'condition': lambda s: True, 'action': None}
]
# 执行规则
for i, rule in enumerate(rules):
if rule['condition'](state):
if rule['action'] is not None:
rule['action'](state)
break
```