java如何解析json对象

在Java中解析JSON对象可以使用Java自带的org.json库或者第三方库如Jackson、Gson等。

使用org.json库解析JSON对象的示例代码：

import org.json.*;

String jsonString = "{\"name\":\"John\", \"age\":30, \"city\":\"New York\"}";

JSONObject jsonObject = new JSONObject(jsonString);

String name = jsonObject.getString("name");
int age = jsonObject.getInt("age");
String city = jsonObject.getString("city");

使用Jackson库解析JSON对象的示例代码：

import com.fasterxml.jackson.databind.ObjectMapper;

String jsonString = "{\"name\":\"John\", \"age\":30, \"city\":\"New York\"}";

ObjectMapper objectMapper = new ObjectMapper();

Map<String, Object> jsonMap = objectMapper.readValue(jsonString, new TypeReference<Map<String, Object>>(){});

String name = (String) jsonMap.get("name");
int age = (int) jsonMap.get("age");
String city = (String) jsonMap.get("city");

使用Gson库解析JSON对象的示例代码：

import com.google.gson.*;

String jsonString = "{\"name\":\"John\", \"age\":30, \"city\":\"New York\"}";

Gson gson = new Gson();

Map<String, Object> jsonMap = gson.fromJson(jsonString, new TypeToken<Map<String, Object>>(){}.getType());

String name = (String) jsonMap.get("name");
int age = (int) jsonMap.get("age");
String city = (String) jsonMap.get("city");