51单片机动态显示2003928
时间: 2023-07-02 20:10:52 浏览: 40
我可以提供一个基本的代码框架来动态显示数字:
```
#include <reg51.h>
// 定义数码管段选IO口
sbit LED_A = P1^0;
sbit LED_B = P1^1;
sbit LED_C = P1^2;
sbit LED_D = P1^3;
sbit LED_E = P1^4;
sbit LED_F = P1^5;
sbit LED_G = P1^6;
// 定义数码管位选IO口
sbit LED_1 = P2^0;
sbit LED_2 = P2^1;
sbit LED_3 = P2^2;
sbit LED_4 = P2^3;
// 定义数字对应的段选状态
unsigned char LED_Digit[] = {
0xC0, // 0
0xF9, // 1
0xA4, // 2
0xB0, // 3
0x99, // 4
0x92, // 5
0x82, // 6
0xF8, // 7
0x80, // 8
0x90 // 9
};
void delay(unsigned int n)
{
unsigned int i,j;
for(i=0;i<n;i++)
for(j=0;j<125;j++);
}
// 数码管显示函数
void LED_Display(unsigned int num)
{
unsigned char i;
unsigned char digit[4];
digit[0] = num/1000;
digit[1] = num%1000/100;
digit[2] = num%100/10;
digit[3] = num%10;
// 数码管位选
LED_1 = 0;
LED_2 = 1;
LED_3 = 1;
LED_4 = 1;
// 数码管段选
for(i=0;i<4;i++)
{
P1 = LED_Digit[digit[i]];
switch(i)
{
case 0: LED_1 = 1; LED_2 = 0; LED_3 = 0; LED_4 = 0; break;
case 1: LED_1 = 0; LED_2 = 1; LED_3 = 0; LED_4 = 0; break;
case 2: LED_1 = 0; LED_2 = 0; LED_3 = 1; LED_4 = 0; break;
case 3: LED_1 = 0; LED_2 = 0; LED_3 = 0; LED_4 = 1; break;
}
delay(5); // 延时5ms,控制数码管刷新速度
}
}
void main()
{
unsigned int num = 2003928;
while(1)
{
LED_Display(num);
}
}
```
请注意,此代码仅用于演示目的。具体实现可能需要根据不同的硬件环境和具体需求进行调整和修改。