怎么将下面两个列表中的元素分别一一对应并且放入下面这段程序中去呢? [{"url": "https://www.example1.com", "index": "1", "post": ""}, {"url": "https://www.example2.com", "index": "2", "post": ""}, {"url": "https://www.example3.com", "index": "3", "post": ""}] url_cookie_list = [ "a=1","a=123"] network_check_req = { "type": "task", "user": "jasonshuang", "content": { "type": "network_check", "urls": [], "task_realip": "", "task_cookie": "", "task_ua": "", "task_referer": "", "task_special_header": {"key1": "val1"} } }
时间: 2023-07-24 18:15:00 浏览: 266
博客https://blog.csdn.net/weixin_49457347/article/details/1236所需文件
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你可以使用zip函数将两个列表中的元素一一对应,并将结果放入指定的程序中。下面是一个示例:
```python
# 两个列表
data_list = [{"url": "https://www.example1.com", "index": "1", "post": ""}, {"url": "https://www.example2.com", "index": "2", "post": ""}, {"url": "https://www.example3.com", "index": "3", "post": ""}]
url_cookie_list = ["a=1", "a=123"]
# 更新network_check_req中的urls和task_cookie
network_check_req["content"]["urls"] = [data["url"] for data in data_list]
network_check_req["content"]["task_cookie"] = url_cookie_list
```
在上面的示例中,我们使用列表解析来创建一个包含所有URL的列表,并将其赋值给了`network_check_req["content"]["urls"]`。同时,我们将`url_cookie_list`赋值给了`network_check_req["content"]["task_cookie"]`。
这样,`network_check_req`中的`urls`和`task_cookie`字段就被更新为对应的列表元素了。
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