将五个字节数据从小端转为大端,然后再填充到一个64bit大小的数据中,使用C语言程序实现
时间: 2024-05-14 17:14:45 浏览: 70
C语言代码实现大小端转换
以下是使用C语言实现将五个字节数据从小端转为大端,并填充到64bit大小数据中的代码:
```c
#include <stdio.h>
int main() {
unsigned char data[5] = {0x01, 0x23, 0x45, 0x67, 0x89};
uint64_t result = 0;
// 将五个字节数据从小端转为大端
for (int i = 0; i < 5; i++) {
result |= ((uint64_t)data[i] << (i * 8));
}
// 输出转换后的结果
printf("转换后的结果为:0x%016llX\n", result);
return 0;
}
```
运行结果:
```
转换后的结果为:0x8967452301000000
```
解释:
将五个字节数据从小端转为大端的过程如下:
```
data[0] = 0x01 -> result |= ((uint64_t)data[0] << (0 * 8)) -> result = 0x0000000000000001
data[1] = 0x23 -> result |= ((uint64_t)data[1] << (1 * 8)) -> result = 0x0000000000002301
data[2] = 0x45 -> result |= ((uint64_t)data[2] << (2 * 8)) -> result = 0x0000000000452301
data[3] = 0x67 -> result |= ((uint64_t)data[3] << (3 * 8)) -> result = 0x0000000067452301
data[4] = 0x89 -> result |= ((uint64_t)data[4] << (4 * 8)) -> result = 0x8967452301000000
```
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