BluetoothDevice device = BluetoothAdapter.getRemoteDevice("20:22:06:15:35:96");中的getRemoteDevice报错
时间: 2023-11-22 11:56:40 浏览: 137
getRemoteDevice() 方法会抛出一个受检查异常 BluetoothDeviceNotFoundException,需要进行异常处理。可以使用 try-catch 块或者在方法声明中使用 throws 关键字。例如:
```
try {
BluetoothDevice device = BluetoothAdapter.getRemoteDevice("20:22:06:15:35:96");
} catch (BluetoothDeviceNotFoundException e) {
// 处理异常
}
```
或者:
```
public void yourMethod() throws BluetoothDeviceNotFoundException {
BluetoothDevice device = BluetoothAdapter.getRemoteDevice("20:22:06:15:35:96");
}
```
需要注意的是,BluetoothAdapter.getRemoteDevice() 方法需要传入一个合法的蓝牙设备地址。如果传入的地址不合法或者设备不可用,会抛出 BluetoothDeviceNotFoundException 异常。
相关问题
import android.bluetooth.BluetoothAdapter; import android.bluetooth.BluetoothDevice; import android.bluetooth.BluetoothSocket; import android.os.Handler; import android.os.Message; import java.io.IOException; import java.io.InputStream; import java.io.OutputStream; import java.util.UUID; public class bluetoothController { private BluetoothAdapter mBluetoothAdapter; private BluetoothSocket mBluetoothSocket; private InputStream mInputStream; private OutputStream mOutputStream; private Handler mHandler; public bluetoothController(Handler handler) { mHandler = handler; mBluetoothAdapter = BluetoothAdapter.getDefaultAdapter(); } public boolean connect(String address) { BluetoothDevice device = mBluetoothAdapter.getRemoteDevice(address); UUID uuid = UUID.fromString("00001101-0000-1000-8000-00805F9B34FB"); try { mBluetoothSocket = device.createRfcommSocketToServiceRecord(uuid); mBluetoothSocket.connect(); mInputStream = mBluetoothSocket.getInputStream(); mOutputStream = mBluetoothSocket.getOutputStream(); return true; } catch (IOException e) { e.printStackTrace(); return false; } } public void disconnect() { try { mBluetoothSocket.close(); } catch (IOException e) { e.printStackTrace(); } } public void write(byte[] bytes) { try { mOutputStream.write(bytes); } catch (IOException e) { e.printStackTrace(); } } public void read() { byte[] buffer = new byte[1024]; int bytes; while (true) { try { bytes = mInputStream.read(buffer); String message = new String(buffer, 0, bytes); Message msg = mHandler.obtainMessage(0, message); mHandler.sendMessage(msg); } catch (IOException e) { e.printStackTrace(); break; } } } }
这是一个蓝牙控制器的 Java 类,它可以连接到指定的蓝牙设备并发送和接收数据。它使用 BluetoothAdapter、BluetoothDevice 和 BluetoothSocket 类来管理蓝牙连接,使用 InputStream 和 OutputStream 类来读写数据。它还使用 Handler 和 Message 类来处理接收到的数据。如果你有任何关于这个类的问题,可以继续问我。
void bondStateChangeCallback(int status, byte[] address, int newState) { BluetoothDevice device = mRemoteDevices.getDevice(address); if (device == null) { infoLog("No record of the device:" + device); // This device will be added as part of the BONDING_STATE_CHANGE intent processing // in sendIntent above device = mAdapter.getRemoteDevice(Utils.getAddressStringFromByte(address)); } infoLog("bondStateChangeCallback: Status: " + status + " Address: " + device + " newState: " + newState); Message msg = obtainMessage(BONDING_STATE_CHANGE); msg.obj = device; if (newState == BOND_STATE_BONDED) { msg.arg1 = BluetoothDevice.BOND_BONDED; } else if (newState == BOND_STATE_BONDING) { msg.arg1 = BluetoothDevice.BOND_BONDING; } else { msg.arg1 = BluetoothDevice.BOND_NONE; } msg.arg2 = status; sendMessage(msg); }sendMessage(msg);再次发出去是同步还是异步发出去的,如果是异步的话,是否有时序的风险
根据给出的代码片段,sendMessage(msg)方法是在bondStateChangeCallback()回调函数内部调用的。根据Android消息机制,sendMessage()方法通常是异步的,消息会被放入消息队列中,然后在适当的时机被处理。因此,sendMessage()方法的调用是异步的。
关于时序风险,如果在sendMessage()方法调用之后立即对msg进行修改或者释放,则可能存在时序风险。因为消息处理可能会在稍后的时间点才会被执行,而修改或释放msg的操作可能会在消息处理之前发生,导致不一致的结果。为了避免时序风险,应该在sendMessage()之后不要对msg进行修改或释放操作。
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