verilog 二进制转bcd

以下是16位二进制转BCD码的Verilog代码示例：

module bin2bcd(
input [15:] bin,
output [3:] bcd,
output [3:] bcd1,
output [3:] bcd2,
output [3:] bcd3
);

reg [3:] bcd_reg, bcd1_reg, bcd2_reg, bcd3_reg;
reg [3:] bcd_next, bcd1_next, bcd2_next, bcd3_next;
reg [3:] bin_reg;
reg [3:] count;

always @ (posedge clk) begin
bin_reg <= bin;
count <= ;
bcd_reg <= ;
bcd1_reg <= ;
bcd2_reg <= ;
bcd3_reg <= ;
end

always @ (posedge clk) begin
if (count < 4) begin
bcd_next = bcd_reg;
bcd1_next = bcd1_reg;
bcd2_next = bcd2_reg;
bcd3_next = bcd3_reg;
if (bin_reg[3:] > 4) begin
bcd_next = bcd_next + 3;
end
if (bin_reg[7:4] > 4) begin
bcd1_next = bcd1_next + 3;
end
if (bin_reg[11:8] > 4) begin
bcd2_next = bcd2_next + 3;
end
if (bin_reg[15:12] > 4) begin
bcd3_next = bcd3_next + 3;
end
if (bin_reg[3:] > 9) begin
bcd_next = bcd_next + 6;
end
if (bin_reg[7:4] > 9) begin
bcd1_next = bcd1_next + 6;
end
if (bin_reg[11:8] > 9) begin
bcd2_next = bcd2_next + 6;
end
if (bin_reg[15:12] > 9) begin
bcd3_next = bcd3_next + 6;
end
bcd_reg <= bcd_next;
bcd1_reg <= bcd1_next;
bcd2_reg <= bcd2_next;
bcd3_reg <= bcd3_next;
count <= count + 1;
end
end

assign bcd = bcd_reg;
assign bcd1 = bcd1_reg;
assign bcd2 = bcd2_reg;
assign bcd3 = bcd3_reg;

endmodule

该代码将16位二进制数转换为4个4位BCD码。在时钟上升沿时，将二进制数存储在寄存器中，并将计数器和BCD码寄存器重置为。然后，对于每个BCD码，将其下一个值设置为当前值，并根据二进制数的每个4位数字进行调整。如果数字大于4，则添加3，如果数字大于9，则添加6。最后，将下一个BCD码值存储回寄存器中。最后，将四个BCD码输出。